Question

我有一个像这样的网址字符串： example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1

是否有可能只使用javascript捕获=之后的部分？所以抓住的部分应该是：uploads/sfm/root/folder1/subfolder1

Answer 1

你可以试试这个（取自MDN）：

var getQueryVarByName = function (name)
{
    name = name.replace(/[\[]/, "\\[").replace(/[\]]/, "\\]");
    var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
        results = regex.exec(location.search);
    return results === null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
};

使用：

var param = getQueryVarByName('dir'); // uploads/sfm/root/folder1/subfolder1

Answer 2

您可以使用split在=分割字符串并获取第二部分

var str = 'example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1';
var part = str.split('=')[1];
console.log(part);

Answer 3

您可以使用.split()获取它：

Working Example

var url = "example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1";

var s = url.split('=')[1];

Answer 4

您可以尝试此操作（使用.split()）：

function getFilePath(fullPath){
    return fullPath.split("dir=")[1];
}

现在按以下方式调用它：

getFilePath("example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1")

Answer 5

您需要创建regexp。如果dir正则表达式之后有更多参数应该更复杂。

＆＃13;

var url = 'example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1';
var regexp = /dir=([\w\W]*)/;
var matched = url.match(regexp);

document.body.innerHTML = matched[1];

＆＃13;

Answer 6

问号?后面的部分称为window.location.search。您可能在此查询字符串中包含1个以上的参数。所以安全的解决方案应该是这样的：

//example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1&un=test&time=1234
function getPath(){
var query=window.location.search //?dir=uploads/sfm/root/folder1/subfolder1&un=test&time=1234
   .replace(/^\?/,'') //dir=uploads/sfm/root/folder1/subfolder1&un=test&time=1234
   .split('&'); //[dir=uploads/sfm/root/folder1/subfolder1, un=test, time=1234]
for(var i = 0, n = query.length;i < n;i++){
   var qs = query[i].split('=');
   if(qs.length == 2 && qs[0] == 'dir')
      return qs[1]; //if found
}//for
return null; // not found
}

如何使用javascript

6 个答案: