Question

在此网址 http://localhost/yitz/Personnel/personnel_filesharing/j12 中，我只获取j12目录中的文件夹/文件，其中j12是用户名会话。

我的问题是我想将j12的文件夹和文件共享给其他用户。我使用where子句，其中表folder_shared_to是将看到共享文件夹内容的用户。我想要我的网址 http://localhost/yitz/Personnel/personnel_filesharing_shared/shared_folders ，其中shared_folders包含与您共享的文件夹。

数据库：

|folder_path      | folder_shared_to|
________________________________
|filesharing/j13  | j12             |

在我的控制器中：

function personnel_filesharing_shared()
{   $this->checkLogin();
     date_default_timezone_set('Asia/Manila');
    $date =date("Y-m-d");
    $newDate = date("F-d-Y", strtotime($date));
    $data['date_today'] = $newDate;
    $data['latest_events'] =  $this->Model_accounts->get_events_latest($date);
    $data['latest_announcements'] =  $this->Model_accounts->get_personnel_announcements_latest();
    $username = $_SESSION['username'];
    $data['count'] = $this->Model_accounts->count_unread($username);

  $user = $_SESSION['username'];
    $site = $_SERVER['REQUEST_URI'];
    $url_arr = explode('/',$site);
    $url_count = count($url_arr);
    $new_url ="";       
    for($x = 4; $x<$url_count;$x++)
    {
        if($x==$url_count-1)
        {
            $new_url.=$url_arr[$x];
        }
        else
        {
            $new_url.=$url_arr[$x]."/";
        }
    }
    $url = $new_url;
     $array = array('folder_path' => $url, 'folder_shared_to' => $user);
    $data['folders'] = $this->db->select('*')->from('personnel_folder')->where($array)->get()->result();
   $data['files'] = $this->db->select('*')->from('personnel_files')->where('file_path',$url)->get()->result();
    $this->load->view('personnel/Personnel_filesharing_shared',$data);
}

CodeIgniter this-＆gt; uri-＆gt;分段多个值

0 个答案: