Question

这是关于迭代值和openMDAO问题的上一个问题的附加组件。我希望能够使用top.run（）计算值。然后检查更改。然而，之前的建议似乎不起作用。

我发现在修改或运行问题时，prob.root.unknowns并没有真正改变。

class TestObj(Component):

    def __init__(self):

        Component.__init__(self)

        self.add_param('x',5.0)
        self.add_output('y',5.0)

    def solve_nonlinear(self,params,unknowns,resids):

        unknowns['y']=params['x']

top = Problem()
root = Group()
top.root=root

root.add('split',IndepVarComp('x',2.0),promotes=['*'])
root.add('test',TestObj(),promotes=['*'])

top.setup()
top.root.list_connections()

print 'starting'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print v['val']
top.run()

print 'after first solve'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print v['val']

top['x']=33.0

print 'after second solve'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print v['val']

top.run()

print 'after third solve'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print v['val']

Answer 1

vec_wrapper上的迭代器返回键上的迭代器和元数据字典。＆＃39; val＆＃39;您在元数据中访问的属性实际上是初始值。

试试这个，你会发现它正在改变：

from openmdao.api import Component, Problem, Group, IndepVarComp

class TestObj(Component):

    def __init__(self):

        Component.__init__(self)

        self.add_param('x',5.0)
        self.add_output('y',5.0)

    def solve_nonlinear(self,params,unknowns,resids):

        unknowns['y']=params['x']

top = Problem()
root = Group()
top.root=root

root.add('split',IndepVarComp('x',2.0),promotes=['*'])
root.add('test',TestObj(),promotes=['*'])

top.setup()
top.root.list_connections()

print 'starting'
print top['x']
print top['y']
for k,v in root.unknowns.iteritems():
    print k
    print top.root.unknowns[k]
top.run()

print 'after first solve'
print top['x']
print top['y']
for k,v in root.unknowns.iteritems():
    print k
    print top.root.unknowns[k]

top['x']=33.0

print 'after second solve'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print top.root.unknowns[k]

top.run()

print 'after third solve'
print top['x']
print top['y']
for k,v in top.root.unknowns.iteritems():
    print k
    print top.root.unknowns[k]

prob.root.unknowns的值不会随着solve而改变

1 个答案: