HTTP状态500 - 请求处理失败;嵌套异常是org.hibernate.QueryException:无法解析属性

时间:2016-05-22 11:46:48

标签: java spring hibernate http-status-code-500

我是Spring MVC和Hibernate的新手,我遇到了一个问题。我已经通过Hibernate创建了Child表,它与User表(Many to One)相连。当Hibernate创建Child表时,会自动添加' user_object_id' - 通过' user_object' (类型用户)这两个表是连接的。但是,当我想向用户展示他的孩子时,就会出现问题:

HTTP Status 500 - Request processing failed; nested exception is org.hibernate.QueryException:
could not resolve property: user_object_id of: com.websystique.springmvc.model.Child

我从findAllUserChilds方法中的ChildDaoImpl类中的表中获取Child对象,然后映射到ChildController中的ChildDTO(POJO对象)。错误与' user_object_id'在Child模型中,因为这个变量不存在,因为它由Hibernate自动创建并由Criteria在findAllUserChilds()中返回。我该如何解决这个问题?

子:

@Entity
@Table(name= "Child")
public class Child implements Serializable
{ 

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;

@Column (nullable=false)
private String first_name;

@Column (nullable=false)
private String last_name;

@Column (nullable=false)
private String birth_city;

@Column (nullable=false)
private String pesel;

@Column (nullable=false)
private String sex;

@Column (nullable=false)
private String blood_group;

@Column (nullable=false)
private String birth_date;


@ManyToOne
private User user_object;

public User getUser_object() {
    return user_object;
}

public void setUser_object(User user_object) {
    this.user_object = user_object;
}

(... 
some getters and setters
...)

}

ChildController:

@RequestMapping(value = "/mainpanel" , method = RequestMethod.GET, 
        headers = "accept=application/json")
public List<ChildDTO> listChild(HttpServletResponse request)
{
    Authentication auth =     SecurityContextHolder.getContext().getAuthentication();

    String username = auth.getName();

    User user = userService.findUserByUsername(username);

    List<Child> list = service.findAllUserChilds(user.getId());

    List<ChildDTO> result = new ArrayList<>();

    for (Child child : list)
    {
        result.add(ChildMapper.map(child));
    }

    return result;
}

ChildDaoImpl:

@Repository("ChildDao")
public class ChildDaoImpl extends AbstractDao<Integer, Child> implements     ChildDao {

@SuppressWarnings("unchecked")
public List<Child> findAllUserChilds(int user_id)
{
    Criteria criteria = createEntityCriteria();
    criteria.add(Restrictions.eq("user_object_id", user_id));
    return (List<Child>) criteria.list();
}

}

1 个答案:

答案 0 :(得分:0)

Child没有propetry user_object_id但没有user_object。 您必须使用user_object.id(如果id是User中的属性名称)