Question

我想检查数据框的变量是否至少包含其中一个值。我想要OR函数的R等价物，看起来像这样（这里的OR函数显然是错误的）

lost$League =ifelse(grepl(OR("Academy","H.S.") , lost$Drafted.From), "Highschool","Not highschool")

lost$League将有价值＆＃34; Highschool＆＃34;如果lost$Drafted.From包含＆＃34;学院＆＃34;或者＆＃34; H.S。＆＃34;，并且有价值＆＃34;没有高中＆＃34;否则。

我是R的新手，英语不是我的第一语言，所以如果我的问题不是很清楚，我很抱歉。

Answer 1

这完全取决于单词“contains”的解释。如果Drafted.From列仅包含单个字词或完整（完全）匹配，则垂直管道|或%in%运算符就足够了。否则，您将需要grepl。

一些示例数据：

lost <- data.frame(drafted.from.1 = c('Academy','College','H.S.'),
                   drafted.from.2 = c('He studied at the Academy','She went to College','He attended Dartmore H.S.'))

对于drafted.from.1列，您可以按如下方式使用%in%：

ifelse(lost$drafted.from.1 %in% c("Academy","H.S."), "Highschool", "Not highschool")

给出了正确的结果：

[1] "Highschool"     "Not highschool" "Highschool"

但grepl也适用于这种情况：

> ifelse(grepl("Academy|H.S.", lost$drafted.from.1), "Highschool", "Not highschool")
[1] "Highschool"     "Not highschool" "Highschool"

对于drafted.from.2列，您需要grepl分配Highschool和Not highschool值：

ifelse(grepl("Academy|H.S.", lost$drafted.from.2), "Highschool", "Not highschool")

给出了正确的结果：

[1] "Highschool"     "Not highschool" "Highschool"

关于drafted.from.2列，%in%（或使用| OR运算符）不会给出正确的结果：

> ifelse(lost$drafted.from.2 %in% c("Academy","H.S."), "Highschool", "Not highschool")
[1] "Not highschool" "Not highschool" "Not highschool"

现在让我们将这些知识应用于数据框：

lost$League.1 <- ifelse(lost$drafted.from.1 %in% c("Academy","H.S."), "Highschool", "Not highschool")
lost$League.2 <- ifelse(grepl("Academy|H.S.", lost$drafted.from.2), "Highschool", "Not highschool")

结果：

> lost
  drafted.from.1            drafted.from.2       League.1       League.2
1        Academy He studied at the Academy     Highschool     Highschool
2        College       She went to College Not highschool Not highschool
3           H.S.      He finished his H.S.     Highschool     Highschool

Answer 2

使用|（或）运算符，如下所示：

mydf$lost <- ifelse(lost$Drafted.From == "Academy" | lost$Drafted.From == "H.S.", "Highschool", "Not highschool")

OR函数用于R中的字符值

2 个答案: