实际上我正在尝试创建一个复选框,该复选框将根据多个选定的成分显示匹配配方。 (某些食谱可能含有相同的成分)但我不知道如何制作if else
陈述。到目前为止,这是显示所选成分的代码,但它并不完整。有人帮我解释if else
声明。谢谢。 (我正在使用android studio)
public class DessertIngAvail extends Dessert {
ArrayList<String> selection = new ArrayList<String>();
TextView final_text;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_dessert_ing_avail);
final_text = (TextView)findViewById(R.id.final_result);
final_text.setEnabled(false);
}
public void selectItem(View view){
boolean checked = ((CheckBox) view).isChecked();
switch (view.getId())
{
case R.id.checkBox153:
if(checked)
{if(!selection.contains("Bingka Cheese"))
selection.add("Bingka Cheese");
}
break;
case R.id.checkBox154:
if(checked)
{if(!selection.contains("Bingka Cheese"))
selection.add("Bingka Cheese");
if(!selection.contains("Steam Shrimp Paste Cake"))
selection.add("Steam Shrimp Paste Cake");
if(!selection.contains("Banana Heart Cake"))
selection.add(" Banana Heart Cake");
if(!selection.contains("Honey Frankincense Cake"))
selection.add(" Honey Frankincense Cake");
if(!selection.contains("Ray Heart Cake"))
selection.add("Ray Heart Cake");
}
break;
case R.id.checkBox155:
if(checked)
{if(!selection.contains("Bingka Cheese"))
selection.add("Bingka Cheese");
if(!selection.contains("Steam Shrimp Paste Cake"))
selection.add("Steam Shrimp Paste Cake");
if(!selection.contains("Banana Heart Cake"))
selection.add("Banana Heart Cake");
if(!selection.contains("Evergreen Cake"))
selection.add("Evergreen Cake");
if(!selection.contains("Moss Cake"))
selection.add("Moss Cake");
if(!selection.contains("Honey Frankincense Cake"))
selection.add("Honey Frankincense Cake");
if(!selection.contains("Ray Heart Cake"))
selection.add("Ray Heart Cake");
}
break;
case R.id.checkBox156:
if(checked)
{if(!selection.contains("Bingka Cheese"))
selection.add("Bingka Cheese");}
break;
case R.id.checkBox157:
if(checked)
{if(!selection.contains("Bingka Cheese"))
selection.add("Bingka Cheese");
if(!selection.contains("Steam Shrimp Paste Cake"))
selection.add("Steam Shrimp Paste Cake");
if(!selection.contains("Evergreen Cake"))
selection.add("Evergreen Cake");
if(!selection.contains("Moss Cake"))
selection.add("Moss Cake");
}
break;
}
}
public void finalSelection(View view){
String final_fruit_selection = "";
for(String Selection : selection)
{
final_fruit_selection = final_fruit_selection + Selection + "\n";
}
final_text.setText(final_fruit_selection);
final_text.setEnabled(true);
}
}
代码的问题是,我无法删除已检查成分的第一个输出。因此,当我第二次输入检查成分时,检查成分的值只是保持添加而不删除先前的结果。
答案 0 :(得分:0)
首先使用A1, A2
20294 Lorenzana Dr
Woodland Hills, CA
91364
B1, B2
19831 Henshaw St
Culver City, CA
94023
C1, C2
5142 Dumont Pl
Azusa, CA
91112
D1, D2
20636 De Forest St
Woodland Hills, CA
91364
A1, A2
20294 Lorenzana Dr
Woodland Hills, CA
91364
E1, E2
4851 Poe Ave
Woodland Hills, CA
91364
F1, F2
20225 Lorenzana Dr
Los Angeles, CA
91111
G1, G2
20253 Lorenzana Dr
Los Angeles, CA
90005
H1, H2
5241 Del Moreno Dr
Los Angeles, CA
91110
I1, I2
5332 Felice Pl
Stevenson Ranch, CA
94135
J1, J2
5135 Quakertown Ave
Thousand Oaks, CA
91362
K1, K2
720 Eucalyptus Ave 105
Inglewood, CA
89030
L1, L2
5021 Dumont Pl
Woodland Hills, CA
91364
M1, M2
4819 Quedo Pl
Westlake Village, CA
91362
I1, I2
5332 Felice Pl
Stevenson Ranch, CA
94135
I1, I2
5332 Felice Pl
Stevenson Ranch, CA
94135
N1, N2
20044 Wells Dr
Beverly Hills, CA
90210
O1, O2
7659 Mckinley Ave
Los Angeles, CA
90001
(HashSet)来避免
Set
其次我会做这样的事情。将成分名称设置为if(!selection.contains("Ray Heart Cake")){
selection.add("Ray Heart Cake");
}
或View#setTag()
,其中Map<Integer, String>
是视图ID:
Integer
这将使您的代码更易读,更容易。