我正在Linux下编写一个简单的python脚本,使用subprocess
对我子网中的主机进行一批并发单行ping。
手动命令有效:
ping -c 1 192.168.68.1
脚本::
#!/usr/bin/python
from subprocess import call
path = "ping"
flags = "-c 1 "
for i in range(1,3):
ip_addr = "192.168.68." + str(i)
args = flags + ip_addr
print "doing: {} {}".format(path, args)
call([path, args])
评论出预期的电话输出:
doing: ping -c 1 192.168.68.1
doing: ping -c 1 192.168.68.2
使用call()
,脚本似乎调用ping但参数未知。输出如下:
doing: ping -c 1 192.168.68.1
Usage: ping [-aAbBdDfhLnOqrRUvV64] [-c count] [-i interval] [-I interface]
[-m mark] [-M pmtudisc_option] [-l preload] [-p pattern] [-Q tos]
[-s packetsize] [-S sndbuf] [-t ttl] [-T timestamp_option]
[-w deadline] [-W timeout] [hop1 ...] destination
Usage: ping -6 [-aAbBdDfhLnOqrRUvV] [-c count] [-i interval] [-I interface]
[-l preload] [-m mark] [-M pmtudisc_option]
[-N nodeinfo_option] [-p pattern] [-Q tclass] [-s packetsize]
[-S sndbuf] [-t ttl] [-T timestamp_option] [-w deadline]
[-W timeout] destination
doing: ping -c 1 192.168.68.2
Usage: ping [-aAbBdDfhLnOqrRUvV64] [-c count] [-i interval] [-I interface]
[-m mark] [-M pmtudisc_option] [-l preload] [-p pattern] [-Q tos]
[-s packetsize] [-S sndbuf] [-t ttl] [-T timestamp_option]
[-w deadline] [-W timeout] [hop1 ...] destination
Usage: ping -6 [-aAbBdDfhLnOqrRUvV] [-c count] [-i interval] [-I interface]
[-l preload] [-m mark] [-M pmtudisc_option]
[-N nodeinfo_option] [-p pattern] [-Q tclass] [-s packetsize]
[-S sndbuf] [-t ttl] [-T timestamp_option] [-w deadline]
[-W timeout] destination
对于每次迭代,似乎ping
被调用两次,其中args
与我期望的不同。我注意到ping -6
论证抱怨。
我将不胜感激,尤其是在正确使用call()
方面。
更新
添加了bash脚本我试图模仿:
#!/bin/bash
for ip in $(seq 1 2); do
ping -c 1 192.168.68.$ip &
done
答案 0 :(得分:2)
传递给函数call
的参数应该是列表中的单个元素,如下所示:
call(['ping','-c','1','192.168.68.2'])
我无法重现'双重打印'在我的环境中。
答案 1 :(得分:0)
由于@Pablo提到flags
和path
变量应该是一个列表元素,所以在调用call
方法之前只需将命令字符串转换为list:
path = "ping"
flags = "-c 1"
cmd_list = [path] # convert string to list
cmd_list = cmd_list + flags.split(' ') # converting your flags string to list elements
call(cmd_list)