优化playbook使其成为幂等的shell模块

时间:2016-05-22 05:32:57

标签: ansible ansible-playbook idempotent

我正在使用ansible自动执行堆栈部署。我使用“shell”或“c​​ommand”模块来执行大部分任务。所以为了使playbook与shell和模块幂等,我正在修改这样的剧本..

- name: Task1
  shell: 'source /etc/nova/openrc && heat stack-show myne01 | tee stack_show.log'
  args:
    creates: stack_show.log
  register: list
- debug: var=list.stdout_lines
  ignore_errors: yes

- name: Delete stack-show.log
  file: path=/home/wrsroot/stack_show.log state=absent
  when: "list.rc != 0"

- name: Failed the stack
  shell: "echo 'stack is failed'"
  when: "list.rc != 0"
  failed_when: "list.rc != 0"

这里的流程是:

1)显示堆栈状态
2)如果堆栈执行失败,则忽略错误并删除“stack_show.log”文件,因此在重新运行anisble时不会跳过此任务。
3)如果堆栈执行失败,则任务失败。

请建议是否有更好的方法来做到这一点。

为了在playbook中添加幂等性,我为每个“shell”模块添加了9行代码。它使我的剧本非常大。

1 个答案:

答案 0 :(得分:0)

您只需要changed_when: false是幂等的。 另外我认为你可以更简单地做到这一点:

- name: Task1
  shell: bash -c 'set -o pipefail;source /etc/nova/openrc && heat stack-show myne01 | tee stack_show.log'
  changed_when: false
  args:
    creates: stack_show.log
  register: list

- name: Delete stack-show.log
  file: path=/home/wrsroot/stack_show.log state=absent
  changed_when: false
  # You don't need this because file will deleted if exists
  #  when: "list.rc != 0"

# You don't need it because command will failed 
# set -o pipefail
#- name: Failed the stack
#  shell: "echo 'stack is failed'"
#  when: "list.rc != 0"
#  failed_when: "list.rc != 0"

你试试Ansible 2.x Blocks

tasks:
     - block:
         - shell: bash -c 'set -o pipefail;source /etc/nova/openrc && heat stack-show myne01 | tee stack_show.log'
           changed_when: false
           args:
              creates: stack_show.log
            register: list

       always:
         - debug: msg="this always executes"    
         - name: Delete stack-show.log
              file: path=/home/wrsroot/stack_show.log state=absent
              changed_when: false