sql结果中的附加列

Question

给出以下MySQL语句：

SELECT name FROM jobtype_descriptions WHERE id IN (SELECT job_description FROM `table2` WHERE id IN (10684,10580,10583,10582,10581,10579,10576))

执行时，它会给我以下结果：

但是我希望将内部select语句中的ids job_description列包含为第一列。这是内部select语句的结果：

我尝试使用第二个select语句的别名，但没有用。

Answer 1

您需要按名称包含所需的列，即

SELECT id, name FROM jobtype_descriptions WHERE id IN (SELECT job_description FROM `table2` WHERE id IN (10684,10580,10583,10582,10581,10579,10576))

Answer 2

将您的查询修改为

SELECT t2.id, jtd.name 
FROM jobtype_descriptions jtd
JOIN table2 t2 ON jtd.id = t2.job_description
WHERE t2.id IN (10684,10580,10583,10582,10581,10579,10576);

Answer 3

尝试

SELECT name, id FROM jobtype_descriptions WHERE id IN (SELECT job_description FROM `table2` WHERE id IN (10684,10580,10583,10582,10581,10579,10576))

您通常可以通过按名称引用它们来在选择中包含所需的任何列。例如，SELECT col1, col2, col3 FROM ...