我有以下表格
videos
id | title | url
video_to_category
video_id | category_id
我想要一个查询来获取视频表中具有某个category_id的所有视频
答案 0 :(得分:1)
SELECT * FROM videos v, video_to_category vc
WHERE v.id=vc.video_id AND category_id=YOURID
答案 1 :(得分:1)
您可以使用内部联接
select a.*
from videos as a
inner join video_to_category as b on a.id = b.video_id
and b.category_id = 'Your_value';
答案 2 :(得分:1)
SELECT * FROM `videos` AS `v`,`video_to_category` AS `vtc`
WHERE `v`.`id`=`vtc`.`video_id`
AND `vtc`.`category_id`='YOUR CHOICE'
OR
SELECT * FROM `videos` `v` INNER JOIN `video_to_category` `vtc`
ON `v`.`id`=`vtc`.`video_id`
AND `vtc`.`category_id`='YOUR CHOICE'
答案 3 :(得分:1)
select videos.* from videos
inner join video_to_category
on video_to_category.video_id = videos.id
and video_to_category.category_id = 10
通过分析您的表格,您的列video_to_category似乎只有2列,如果是这种情况,那么您不需要将其保存在不同的列中,您可以在视频表名称中添加新列' category_id& #39;,但如果您在此问题中隐藏了其他一些列,请将其保留。
答案 4 :(得分:1)
select vi.id, vi.title, vi.url from videos vi left join video_to_category
vc on (vi.id = vc.video_id) where vc.category_id = '$category_id'
$ category_id是放置给定变量id的变量。我使用“$”因为我在这里使用php varaiable。
由于