Question

我的代码可能有什么问题？当我运行它时，我继续在浏览器中收到此错误＆＃34;警告：mysqli_query（）期望参数1为mysqli，C：\ wamp中给出的整数第4行\ www \ login \ core \ function \ users.php ＆＃34; ..我需要帮助。我的代码如下：

user.php的

<?php
require('core/database/connect.php');
global $username;
function user_exists($con,$username){
$username = sanitize($username);
$query = mysqli_query($con,"SELECT COUNT(`user_id`) FROM `users` WHERE  `username` = '$username'") OR  die(mysqli_error());
return (mysqli_fetch_assoc($query) ==1) ? true : false;
}
function user_active($username){
$username = sanitize($username);
$query = mysqli_query($con,"SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `active` = 1") OR  die(mysqli_error());
return (mysqli_fetch_assoc($query) ==1) ? true : false;
}
?>

** connect.php ***

<?php
$connect_error = 'sorry,we are experiencing connection problem.';
$con = mysqli_connect('localhost','root','') or die($connect_error);

mysqli_select_db($con,'login_registration') or die($connect_error);

?>

函数调用

<?php
include 'core/init.php';

if(empty($_POST) === false){
$username = $_POST['username'];
$password = $_POST['password'];

if(empty($username) || empty($password)){
    $errors[] = 'You need to enter a username and password';
}else if(user_exists($con,$username) === false){
    $errors[] = 'The account dosen\'t exit.Please register';
}else if(user_active($username ) === false){
    $errors[] = 'Please u have not login into ur account';
}else{
    //here
}
print_r($errors);
}
?>

请告诉我我的代码有什么问题。提前谢谢

Answer 1

将mysqli_connect打开的新连接存储在变量中，然后将connection.php包含在另一个文件中，并在user.php中使用该变量。

<强> connection.php

<?php
    $con = mysqli_connect('127.0.0.1','root','');
?>

<强> user.php的

<?php
    require_once($_SERVER['DOCUMENT_ROOT'] .  'Project Name/' .  'core/database/connection.php');

    function user_exists($username){
        $username = sanitize($username);
        $query = mysqli_query($con, "SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username'") OR die(mysql_error());
        return (mysql_result($query,0) ==1) ? true : false;
    }

   function user_active($username){
        $username = sanitize($username);
        $query = mysqli_query($con, "SELECT COUNT(`user_id`) FROM `users` WHERE `username` = '$username' AND `active` = 1")  OR  die(mysql_error());
        return (mysql_result($query,0) ==1) ? true : false;
    }
?>

警告：mysqli_query（）期望参数1为mysqli，给定整数

1 个答案: