无法处理托管/后向引用'defaultReference':找不到后引用属性

时间:2016-05-21 16:38:38

标签: java json spring rest

我有两个模型类。一个是

@Entity(name = "userTools")
@Table(uniqueConstraints = @UniqueConstraint(columnNames = { "assignToUser_id","toolsType_id" }))
@Inheritance(strategy = InheritanceType.JOINED)
@JsonTypeInfo(use = JsonTypeInfo.Id.CLASS, include = JsonTypeInfo.As.PROPERTY, property = "className")
@JsonIgnoreProperties(ignoreUnknown = true)
public class UserTools {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @OneToOne
    private ToolsType toolsType;

    @OneToMany(mappedBy = "userTools", fetch = FetchType.EAGER, cascade = { CascadeType.ALL }, orphanRemoval = true)
    @Cascade(org.hibernate.annotations.CascadeType.DELETE)
    @JsonManagedReference
    private List<UserToolsHistory> userToolsHistory;
}

,第二个是

@Entity(name = "userToolsHistory")
@JsonIgnoreProperties(ignoreUnknown = true)
public class UserToolsHistory {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @OneToOne
    private ToolsType toolsType;

    @ManyToOne
    @JsonIgnore
    @JsonBackReference
    private UserTools userTools; 

    private String comments;
}

但是在保存时我收到了这个错误:

Can not handle managed/back reference 'defaultReference': no back
reference property found from type [collection type; class
java.util.List, contains [simple type, class
com.dw.model.tools.UserToolsHistory]]

3 个答案:

答案 0 :(得分:7)

您遇到的异常源于MappingJackson2HttpMessageConverter。

要修复它,请交换注释,以便得到:

public class UserTools {
...
@JsonBackReference
private List<UserToolsHistory> userToolsHistory;
...
}

public class UserToolsHistory {
....    
@JsonManagedReference
private UserTools userTools; 
----
}

本教程解释了必须如何完成:jackson-bidirectional-relationships-and-infinite-recursion

答案 1 :(得分:7)

为了简化问题排查,您可以为每个@JsonManagedReference@JsonBackReference添加不同的名称,例如:

@JsonManagedReference(value="userToolsHistory")
    private List<UserToolsHistory> userToolsHistory;

这样,错误更有意义,因为它打印引用名称而不是'defaultReference'。

请指出您尝试序列化的内容 - UserToolsUserToolsHistory?无论如何,您可以尝试将getter和setter添加到您的实体,然后将@JsonIgnore添加到“child”类中的“get {Parent}()”。

答案 2 :(得分:3)

@JsonManagedReference@JsonBackReference并将其替换为@JsonIdentityInfo