Question

我使用Angular 1.5。我有一个查询类别的函数，然后对于每个类别，它查询产品。我想在检索完所有产品后显示一条消息，检索了多少产品。它输出0.解决方案是什么？

function getProducts() {
  vm.categories = [];
  var prodcount = 0;

  $http.get("localhost/menu/1/categories")
    .then(function(response) {
      var categories = response.data;
      angular.forEach(categories, function(cat) {
        $http.get("localhost/category/" + cat.id + "/products")
          .then(function(response) {
            cat.products = response.data;
            vm.categories.push(cat);
            prodcount += cat.products.length;
          });
      });
      $mdToast.show($mdToast.simple().textContent("retrieved " + vm.categories.length + " categories and, " + prodcount + " products!."));
    });
}

Answer 1

您应该了解异步请求和承诺的工作原理。要使代码运行，您可以这样做： var promises = []; //创建一个数组来存储承诺

angular.forEach(categories, function(cat) {

    // Capture the promise
    var requestPromise = $http.get(...)
    .then(function(response) {
        ...
    });
    promises.push(requestPromise);  // Add it to the array
  });

  // This promise will be resolved when all promises in the array have been resolved as well.
  $q.all(promises).then(function(){
     $mdToast.show(...);
  })

});

但这种方法并不是很好。你应该尽量减少请求的数量，最好只做一个。

http://www.martin-brennan.com/using-q-all-to-resolve-multiple-promises/ http://andyshora.com/promises-angularjs-explained-as-cartoon.html

Answer 2

您可以将您的类别数组映射到一组承诺中，然后使用$q.all等待它们全部完成

function getProducts() {
    vm.categories = [];
    var prodcount = 0;

    $http.get("localhost/menu/1/categories")
            .then(function (response) {
                var categories = response.data;
                $q.all(categories.map(function (cat) {
                    return $http.get("localhost/category/" + cat.id + "/products")
                            .then(function (response) {
                                cat.products = response.data;
                                vm.categories.push(cat);
                                prodcount += cat.products.length;
                            });
                })).then(function () {
                    $mdToast.show($mdToast.simple().textContent("retrieved " + vm.categories.length + " categories and, " + prodcount + " products!."));
                });
            });
}

for循环中的递归$ http.get

2 个答案: