如何访问循环外的所有值或数组？我想在循环外访问它是因为我需要根据availableID对它们进行分组。我试图将它们分组到循环中，结果不像我预期的那样..
预期结果：
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013438096 Hello 1025 1003 7 7 null
2013339255 Hello 1024 1001 7 7 null
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013366609 Hello 1027 1013 2 2 null
2011679914 Hello 1015 1014 2 2 null
2013765397 Hello 1026 1014 2 2 null
但事实证明是这样的：
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013339255 Hello 1024 1001 7 7 null
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013438096 Hello 1025 1003 7 7 null
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013765397 Hello 1026 1014 2 2 null
Student Name Project Title Supervisor Name Examiner Name Start End Date
2011679914 Hello 1015 1014 2 2 null
Student Name Project Title Supervisor Name Examiner Name Start End Date
2013366609 Hello 1027 1013 2 2 null
我想我应该将它们分组到循环之外，所以这是我的逻辑：
try{
String studentName = null;
String projectTitle = null;
String SVName = null;
String EXName = null;
int availID = 0;
String day = null;
Time start = null;
Time end = null;
Date date = null;
for (int i=0 ; i<studentID.length ; i++){
List<Object[]> list = (List<Object[]>) GenerateScheduleDAO.getFree(supervisorID[i],examinerID[i],studentID[i]);
Object[] array = null;
if(!list.isEmpty()){
//declaring the variables
studentName = (String) array[7];
....... // all variables
date = (Date) array[3];
}//check list is NOT empty
else if (list.isEmpty()){
list = (List<Object[]>) GenerateScheduleDAO.getOtherFree(examinerID[i], supervisorID[i],studentID[i]);
//declaring the variables
studentName = (String) array[7];
....... // all variables
date = (Date) array[3];
}
}//student loop
if (availID == 2) {
out.println("<br><center><table id=\"t01\"><tr>"
+ "<th>7Student Name</th>"
+ "<th>Project Title</th>"
+ "<th>Supervisor Name</th>"
+ "<th>Examiner Name</th>"
+ "<th>Day</th>"
+ "<th>Start</th>"
+ "<th>End</th>"
+ "<th>Date</th>"
+ "</tr>");
out.println("<tr>");
out.println("<td>"+ studentName+"</td>");
out.println("<td>"+ projectTitle +"</td>");
out.println("<td>"+ SVName +"</td>");
out.println("<td>"+ EXName +"</td>");
out.println("<td>"+ day +"</td>");
out.println("<td>"+ start +"</td>");
out.println("<td>"+ end+"</td>");
out.println("<td>"+ date+"</td>");
out.println("</tr>");
out.println("</center></table><br><br>");
}//2
else if (availID == 7) {
//Table consist of same attribute as above
}//7
if (availID == 10) {
//Table consist of same attribute as above
}//10
if (availID == 16) {
//Table consist of same attribute as above
}//16
else if (availID != 2 && availID != 7 && availID != 10 && availID == 16) {
//Table consist of same attribute as above
}//else
}// first try
此代码只能检索数组的最后一个值。但我想访问数组的所有数据..我该如何解决这个问题？或者我是否必须逐个嵌套循环每个条件？
答案 0 :(得分：0)
在您的所有设置中，可能会更难以使用。我已经重写了你正在尝试的东西以及availId的所有内容。我在记事本中打了这个，所以请原谅任何问题。
public class StudentExam {
String studentName = null;
String projectTitle = null;
String SVName = null;
String EXName = null;
int availID = 0;
String day = null;
Time start = null;
Time end = null;
Date date = null;
public StudentExam(Object[] studentExamArray){
this.studentName = studentExamArray[7];
this.projectTitle = studentExamArray[]; //TODO Insert index
this.SVName = studentExamArray[]; //TODO Insert index
this.EXName = studentExamArray[]; //TODO Insert index
this.availID = studentExamArray[]; //TODO Insert index
this.day = studentExamArray[]; //TODO Insert index
this.start = studentExamArray[]; //TODO Insert index
this.end = studentExamArray[]; //TODO Insert index
this.date = studentExamArray[3]; //TODO Insert index
}
}
public static void main(String[] args){
List<Object[]> list;
try{
List<Object[]> list = (List<Object[]>)GenerateScheduleDAO.getFree(supervisorID[i],examinerID[i],studentID[i]);
} catch (Exception e){
e.printstacktrace();
// Do something ?
}
if(list == null || list.size() == 0){
return; // Or throw exception
}
List<StudentExam> studentExams = new ArrayList(); // here you can change the list implimentation and use to make a sorted list using a comparator or we can sort it later
for(Object[] studenExamArray : list){
StudenExam studentExam = new StudentExam(studenExamArray);
studentExams.add(studentExam);
}
// Now that you have parsed your data you can go ahead and sort it, and print it the way you want...
Collections.sort(list, new Comparator() {
@Override
public int compare(StudentExam se1, StudentExam se2) {
return Integer.compare(se1.availID, se2.availID)
}
});
for(StudentExam studenExam : studentExams){
switch(studentExam.availID){
case 0:{
// Do stuff
break;
}
case 0:{
// Do stuff
break;
}
case 0:{
// Do stuff
break;
}
case 0:{
// Do stuff
break;
}
case 0:{
// Do stuff
break;
}
}
}
}