这里有一个包含一组重复ID的数组,每个id都被设置为数组键,子数组包含一个id列表,这些ID在同一个数组中也有另一个数组?
DUPLICATES 16
array(16) {
[19503804]=>
array(3) {
[0]=>
string(8) "19501594"
[1]=>
string(8) "15539642"
[2]=>
string(8) "19498944"
}
[19501594]=>
array(3) {
[0]=>
string(8) "19503804"
[1]=>
string(8) "15539642"
[2]=>
string(8) "19498944"
}
[19837033]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19854553"
[3]=>
string(8) "19854565"
[4]=>
string(8) "19854554"
[5]=>
string(8) "19854683"
}
[19854553]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19837033"
[3]=>
string(8) "19854565"
[4]=>
string(8) "19854554"
[5]=>
string(8) "19854683"
}
[19544216]=>
array(3) {
[0]=>
string(8) "19524884"
[1]=>
string(8) "19560234"
[2]=>
string(8) "19540264"
}
[19854565]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19837033"
[3]=>
string(8) "19854553"
[4]=>
string(8) "19854554"
[5]=>
string(8) "19854683"
}
[19854554]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19837033"
[3]=>
string(8) "19854553"
[4]=>
string(8) "19854565"
[5]=>
string(8) "19854683"
}
[15539642]=>
array(3) {
[0]=>
string(8) "19503804"
[1]=>
string(8) "19501594"
[2]=>
string(8) "19498944"
}
[19844271]=>
array(1) {
[0]=>
string(8) "19341140"
}
[19498944]=>
array(3) {
[0]=>
string(8) "19503804"
[1]=>
string(8) "19501594"
[2]=>
string(8) "15539642"
}
[16399898]=>
array(1) {
[0]=>
string(8) "15436391"
}
[15436391]=>
array(1) {
[0]=>
string(8) "16399898"
}
[19341140]=>
array(1) {
[0]=>
string(8) "19844271"
}
[19560234]=>
array(3) {
[0]=>
string(8) "19544216"
[1]=>
string(8) "19524884"
[2]=>
string(8) "19540264"
}
[19854683]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19837033"
[3]=>
string(8) "19854553"
[4]=>
string(8) "19854565"
[5]=>
string(8) "19854554"
}
[19540264]=>
array(3) {
[0]=>
string(8) "19544216"
[1]=>
string(8) "19524884"
[2]=>
string(8) "19560234"
}
}
注意第一个数组?
[19503804]=>
array(3) {
[0]=>
string(8) "19501594"
[1]=>
string(8) "15539642"
[2]=>
string(8) "19498944"
}
“19501594”“15539642”“19498944”还有另一个需要取消设置的数组。所以在这个数组的最后只给出了具有唯一值的唯一数组。
,这是所需的预期输出。
array(5) {
[19503804]=>
array(3) {
[0]=>
string(8) "19501594"
[1]=>
string(8) "15539642"
[2]=>
string(8) "19498944"
}
[19837033]=>
array(6) {
[0]=>
string(8) "19854557"
[1]=>
string(8) "19854558"
[2]=>
string(8) "19854553"
[3]=>
string(8) "19854565"
[4]=>
string(8) "19854554"
[5]=>
string(8) "19854683"
}
[19544216]=>
array(3) {
[0]=>
string(8) "19524884"
[1]=>
string(8) "19560234"
[2]=>
string(8) "19540264"
}
[19844271]=>
array(1) {
[0]=>
string(8) "19341140"
}
[16399898]=>
array(1) {
[0]=>
string(8) "15436391"
}
}
这是我最初编码为@Dale在下面的答案中提出的。
$theduplicates = array (
19503804 =>
array (
0 => '19501594',
1 => '15539642',
2 => '19498944',
),
19501594 =>
array (
0 => '19503804',
1 => '15539642',
2 => '19498944',
),
19837033 =>
array (
0 => '19854557',
1 => '19854558',
2 => '19854553',
3 => '19854565',
4 => '19854554',
5 => '19854683',
),
19854553 =>
array (
0 => '19854557',
1 => '19854558',
2 => '19837033',
3 => '19854565',
4 => '19854554',
5 => '19854683',
),
19544216 =>
array (
0 => '19524884',
1 => '19560234',
2 => '19540264',
),
19854565 =>
array (
0 => '19854557',
1 => '19854558',
2 => '19837033',
3 => '19854553',
4 => '19854554',
5 => '19854683',
),
19854554 =>
array (
0 => '19854557',
1 => '19854558',
2 => '19837033',
3 => '19854553',
4 => '19854565',
5 => '19854683',
),
15539642 =>
array (
0 => '19503804',
1 => '19501594',
2 => '19498944',
),
19844271 =>
array (
0 => '19341140',
),
19498944 =>
array (
0 => '19503804',
1 => '19501594',
2 => '15539642',
),
16399898 =>
array (
0 => '15436391',
),
15436391 =>
array (
0 => '16399898',
),
19341140 =>
array (
0 => '19844271',
),
19560234 =>
array (
0 => '19544216',
1 => '19524884',
2 => '19540264',
),
19854683 =>
array (
0 => '19854557',
1 => '19854558',
2 => '19837033',
3 => '19854553',
4 => '19854565',
5 => '19854554',
),
19540264 =>
array (
0 => '19544216',
1 => '19524884',
2 => '19560234',
),
)
foreach($theduplicates as $k => $v){
foreach($v as $d){
if(isset($theduplicates[$d])){
unset($theduplicates[$d]);
}
}
// but it totally cleans theduplicates array
array(0) {
}
答案 0 :(得分:2)
对于每次迭代,您要检查已经迭代过的键。因此,您希望跟踪这些键。我会做这样的事情:
$keys = [];
foreach ($main_array as $k => $set) {
if (in_array($k, $keys)) {
unset($main_array[$k]);
continue;
}
foreach ($set as $val) {
$keys[] = $val;
}
}
var_dump($main_array);
此代码也可以使用,但您必须通过引用传递:
foreach ($main_array as &$values) {
foreach ($values as $value) {
if(isset($main_array[$value])) {
unset($main_array[$value]);
}
}
}
答案 1 :(得分:0)
如果我理解你的问题(我怀疑的话),这段代码可以帮助你解决问题
$array = [
0 => [5, 6, 7],
1 => [10],
5 => [10], // to remove
6 => [10], // to remove
7 => [10] // to remove
];
print_r($array);
foreach ($array as $key => $values) {
foreach ($values as $value) {
if(isset($array[$value])) {
unset($array[$value]);
}
}
}
print_r($array);
输出..
Array
(
[0] => Array
(
[0] => 5
[1] => 6
[2] => 7
)
[1] => Array
(
[0] => 10
)
[5] => Array
(
[0] => 10
)
[6] => Array
(
[0] => 10
)
[7] => Array
(
[0] => 10
)
)
Array
(
[0] => Array
(
[0] => 5
[1] => 6
[2] => 7
)
[1] => Array
(
[0] => 10
)
)