Question

我正在尝试使用jython编译一个python程序，它正在抛出错误

C:\jython2.2.1>jython test.py
Traceback (innermost last):
  (no code object) at line 0
  File "test.py", line 30
                    html = html if html else download(url, user_agent).read()
                                ^
SyntaxError: invalid syntax

下面是我的python程序。请让我知道如何解决这个问题。

import sys
import re
import urllib2
import urlparse
from optparse import OptionParser


# regular expression data for each website
VIDEO_DATA = [
    ('youtube.com', '%7C(.*?videoplayback.*?)%2C'),
    ('metacafe.com', '&mediaURL=(.*?)&'),
]
# default user agent to use when downloading
USER_AGENT = 'pytube'
# size of file to download
CHUNK_SIZE = 1024 * 1024



def scrape(url, html=None, user_agent=None, output=None):
    """Scrape video location from given url. 

    Use html instead of downloading if passed.
    Download file to output if passed.
    Return url of video if found, else None
    """
    netloc = urlparse.urlsplit(url).netloc
    for domain, video_re in VIDEO_DATA:
        if domain in netloc:
            html = html if html else download(url, user_agent).read()
            search = re.search(video_re, html)
            if search:
                flash_url = urllib2.unquote(search.group(1))
                if output:
                    print "Downloading flash to `%s'" % output,
                    #open(output, 'wb').write(download(flash_url, user_agent).read())
                    req = download(flash_url, user_agent)
                # testing with keyword in python
                    with open(output, 'wb') as fp:
                        chunk = True
                        while chunk:
                            chunk = req.read(CHUNK_SIZE)
                            if chunk:
                                fp.write(chunk)
                                #fp.flush()
                                print '.',
                                sys.stdout.flush()
                    print
                return flash_url
            else:
                raise PyTubeException('Failed to locate video regular expression in downloaded HTML')
    raise PyTubeException('URL did not match available domains')


def download(url, user_agent=None):
    """Download url and return data
    """
    headers = {'User-Agent' : user_agent}
    req = urllib2.Request(url, None, headers)
    return urllib2.urlopen(req)


class PyTubeException(Exception):
    pass



if __name__ == '__main__':
    # parse command line options
    parser = OptionParser(usage='usage: %prog, [-o <file.flv> -a <user_agent> -s -h] url')
    parser.add_option('-o', '--output', dest='output', help='Output file to download flash file to. If this is not specified file will not be downloaded.')
    parser.add_option('-s', '--sites', action='store_true', default=False, dest='sites', help='Display sites that pytube supports, then quit.')
    parser.add_option('-a', '--agent', dest='user_agent', default=USER_AGENT, help='Set user-agent for downloads.') 
    options, args = parser.parse_args()
    if options.sites:
        print '\n'.join(domain for (domain, reg) in VIDEO_DATA)
    else:
        if args:
            flash_url = scrape(args[0], user_agent=options.user_agent, output=options.output)
            if flash_url:
                print flash_url
        else:
            print 'Need to pass the url of the video you want to download'
            parser.print_help()

Answer 1

就语法而言，Jython 2.2.1（AFAIK）等同于Cpython 2.2.1。导致问题的行使用稍后介绍的三元运算符。解决方案是用if语句替换它。

if not html:
     html = download(url, user_agent).read()

那应该处理语法错误。还有一个with子句需要替换。

with open(output, 'wb') as fp:
    chunk = True
    while chunk:
        chunk = req.read(CHUNK_SIZE)
        if chunk:
            fp.write(chunk)
            #fp.flush()
            print '.',
            sys.stdout.flush()

您可以将其替换为

try:
    fp = open(output, 'w')
    chunk = True
    while chunk:
        chunk = req.read(CHUNK_SIZE)
            if chunk:
                fp.write(chunk)
                #fp.flush()
                print '.',
                sys.stdout.flush()
finally:
    fp.close()

无法使用jython编译python程序

1 个答案: