Question

所以我有一个字符串

"sdfsfsdfdsfsdfsd #.split.#style=background: black;"

我想对它做一些操作我想将#.split.#部分更改为div close标记并打开标记：

str.replace("#.split.#", '</div><div>')

除此之外，我想在style=之后选择并放入div开放标签

这样做的快速程序是什么？请记住，#.split.#style=部分可以在字符串中多次出现，并且style=之后的部分可以在长度上变化，但始终以换行符结束。

修改

我想要实现的是来自这样的字符串：

"sdfsfsdfdsfsdfsd #.split.#style=background: black;
 sdfsfsdfdsfsdfsd #.split.#style=background: red;"

到此：

'sdfsfsdfdsfsdfsd </div><div style="background: black;">
 sdfsfsdfdsfsdfsd </div><div style="background:red;">'

Answer 1

按照你的所作所为，

/* 1 */
{
    "queryPlanner" : {
        "plannerVersion" : 1,
        "namespace" : "test.collection",
        "indexFilterSet" : false,
        "parsedQuery" : {
            "$and" : [ 
                {
                    "contents" : {
                        "$size" : 2
                    }
                }, 
                {
                    "topic" : {
                        "$eq" : "BBB"
                    }
                }, 
                {
                    "contents.headerName" : {
                        "$in" : [ 
                            "Program", 
                            "Start Year"
                        ]
                    }
                }, 
                {
                    "contents.value" : {
                        "$in" : [ 
                            1989, 
                            "BBB"
                        ]
                    }
                }
            ]
        },
        "winningPlan" : {
            "stage" : "KEEP_MUTATIONS",
            "inputStage" : {
                "stage" : "FETCH",
                "filter" : {
                    "$and" : [ 
                        {
                            "contents" : {
                                "$size" : 2
                            }
                        }, 
                        {
                            "contents.headerName" : {
                                "$in" : [ 
                                    "Program", 
                                    "Start Year"
                                ]
                            }
                        }, 
                        {
                            "contents.value" : {
                                "$in" : [ 
                                    1989, 
                                    "BBB"
                                ]
                            }
                        }
                    ]
                },
                "inputStage" : {
                    "stage" : "IXSCAN",
                    "keyPattern" : {
                        "topic" : 1,
                        "contents" : 1
                    },
                    "indexName" : "topic_1_contents_1",
                    "isMultiKey" : true,
                    "isUnique" : false,
                    "isSparse" : false,
                    "isPartial" : false,
                    "indexVersion" : 1,
                    "direction" : "forward",
                    "indexBounds" : {
                        "topic" : [ 
                            "[\"BBB\", \"BBB\"]"
                        ],
                        "contents" : [ 
                            "[MinKey, MaxKey]"
                        ]
                    }
                }
            }
        },
        "rejectedPlans" : []
    }
}

这将得到以下结果：

# Avoid str, it is a function name
text = "sdfsfsdfdsfsdfsd #.split.#style=background: black;"
text.replace("#.split.#", "</div><div ")
# End the tag
text += ">"

修改

分开并重新加入。

>>> text "sdfsfsdfdsfsdfsd </div><div style=background: black;>"

<强> RE-修改

# Avoid str, it is a function name
text = 'sdfsfsdfdsfsdfsd #.split.#style=background: black;\n'
# Split string into sections
text = text.split('\n')
# Do the same thing on each line
for i, s in enumerate(text):
    # Start div tag
    new_text = s.replace('#.split.#', '</div><div ')
    # Add quotes
    new_text = new_text.replace('style=', 'style="')
    new_text = new_text.replace(';', ';"')
    if i != len(text) - 1:
        new_text += '>'
    # Apply changes
    text[i] = new_text
# Join the strings back together with newlines
text = '\n'.join(text)

Answer 2

以下是解决方案：

import re

text="sdfsfsdfdsfsdfsd #.split.#style=background: black\nsdfsfsdfdsfsdfsd #.split.#style=background: red"
matches =  re.findall('.*#.split.#.*', text)
final = ""
for m in matches: 
    parts = re.search("(.*)#.split.#style=(.*)", m) 
    new = '{}</div><div style="{};">'.format(parts.group(1), parts.group(2))
    final += new + "\n"
print final

，结果将是：

sdfsfsdfdsfsdfsd </div><div style="background: black;">
sdfsfsdfdsfsdfsd </div><div style="background: red;">

Python - 从另一个字符串中获取字符串部分

2 个答案: