Question

我为我正在处理的应用编写了以下代码：

$tmp = $this->getConfig()['brandIds'];
$unexpired_brands = array();
$expired_brands = array();

foreach($tmp as $key => $value)
{
    $brand = $this->getBrandModel()->getBrandById($value);
    $currentDate = new \DateTime(date("Y-m-d"));
    $startDate = new \DateTime($brand["startDate"]);
    $expireDate = date_add($startDate, date_interval_create_from_date_string('7 days'));
    // this date right here gets modified and on its original value 7 days are added

    if($currentDate>$expireDate)
    // Checking if current date is bigger than expire date.(Ex. 20.5.2016 > (startDate)+7 days) ? Yes
    // Assumption is that start date is < currentDate
    {
        date_add($brand["startDate"],date_interval_create_from_date_string("7 days"));
        // However?? This one isn't ?? It stays the same as the one that is fetched from
        // the db, which is $brand["startDate"] == currently set on 2016-05-10
        array_push($expired_brands,$brand);
    }
    else
    {
        date_add($brand["startDate"],date_interval_create_from_date_string("7 days"));
        // neither this one is modified ??? How can I modify these date as the one I've shown above??
        array_push($unexpired_brands,$brand);
    }
}

正如您在上面所看到的，我无法修改我从数据库中提取的日期值，并且我能够修改我已创建的本地变量检查currentdate是否大于到期日期......

有人可以帮我解决这个问题吗？谢谢堆!!!“

Answer 1

$brand["startDate"]是约会对象吗？发表var_dump($brand["startDate"])声明;它应该告诉你变量类型。

Answer 2

我明白了

date_add($startDate, date_interval_create_from_date_string('7 days'));

工作但是

date_add($brand["startDate"],date_interval_create_from_date_string("7 days"));

没有工作。

也许它是引用问题的双引号而你没有添加

new \DateTime($brand["startDate"])

更改那些无法使用

的内容

date_add(new \DateTime($brand["startDate"]),date_interval_create_from_date_string('7 days'));

因为你似乎想要做同样的事情。

无法在PHP /添加天数中修改日期

2 个答案: