我必须使用数组:
export PATH="/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin"
$门票:
$tickets = $db->loadObjectList();
$tickets_info = $details['ticket_info'];
$ tickets_info:
array (size=2)
0 =>
object(stdClass)[2924]
public 'price' => string '100.000'
public 'name' => string 'Standard ticket'
1 =>
object(stdClass)[2972]
public 'price' => string '150.000'
public 'name' => string 'Luxus ticket'
我正在尝试将98和50作为'available_tickets'添加到$ ticket数组中,如下所示:
array (size=2)
0 => string '98'
1 => string '50'
我已经尝试过array_merge()并循环播放,但似乎没有什么对我有用。
答案 0 :(得分:0)
我会选择以下解决方案:
foreach ( $tickets as $key => $ticket ) {
if( array_key_exists( $key, $tickets_info ) ) {
$tickets[$key]->available_tickets = $tickets_info[$key];
} else {
trigger_error('There is no equivalence to ticket #' . $key);
}
}
答案 1 :(得分:0)
试试这个:
<?php
$tickets = array( 0 =>array('price' => '100.000','name' => 'Standard ticket'),1 =>array( 'price' => '150.000','name' =>'Luxus ticket'));
$available = array(0=>98,1=>50);
foreach($tickets as $key =>$val)
{
$tickets[$key]['available_tickets'] = $available[$key];
}
echo "<pre>"; print_r($tickets);
?>
这会给你:
Array
(
[0] => Array
(
[price] => 100.000
[name] => Standard ticket
[available_tickets] => 98
)
[1] => Array
(
[price] => 150.000
[name] => Luxus ticket
[available_tickets] => 50
)
)
<强> LIVE DEMO 强>
答案 2 :(得分:0)
您可以使用数组映射执行此操作:
$tickets = array_map(function($a, $b) { $a->available_tickets = $b; return $a; }, $tickets, $tickets_info);
这会给你
Array
(
[0] => stdClass Object
(
[price] => "100.000"
[name] => "Standard ticket"
[tickets_available] => "98"
)
[1] => stdClass Object
(
[price] => "150.000"
[name] => "Deluxe ticket"
[tickets_available] => "50"
)
)