我想让每个雇主和他所有的工作都在工作台上 我无法在for-each中获得EmpID 尝试嵌套for-each但在select =“”中遇到冲突 我尝试将select语句更改为
选择=“EmploymnetService /雇主
并在每个作业值中添加这样的额外目录
value-of select =“@ EmployerJobAds / JobAd / JobId”
但只有每个雇主的第一份工作显而易见:-P
我有以下的xml文件
SELECT clashhid,
TaDah,
DahTaPanz,
PanzTaBist,
BistTaBispan,
BispanTaC ,
mariStatus
FROM asli CROSS JOIN (VALUES ('single'),('married')) AS custs (mariStatus)
和xslt
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="employerStyle.xsl"?>
<EmploymnetService>
<Employer employerId="1">
<EmployerName>Ahmad</EmployerName>
<EmployerAddress>Gaza</EmployerAddress>
<EmployerEmail>ahmad.abuabdou@live.com</EmployerEmail>
<EmployerPhone>0598787121</EmployerPhone>
<EmployerJobAds >
<JobAd JobId="1" >
<jobTitle>Programmer</jobTitle>
<jobDescription>Developer</jobDescription>
<QualificationsRequired>
<QLevel>PhD</QLevel>
<QName>Developer</QName>
<QFaculty>IT</QFaculty>
<QUniversity>Azhar Univircity of Gaza</QUniversity>
<QGrade>Excellent</QGrade>
<gradDate>1995-04-19</gradDate>
</QualificationsRequired>
<ExperienceRequired>
<ExpPosition>Programmer</ExpPosition>
<expDescription>Developer</expDescription>
<expEmployer>Pro</expEmployer>
<expFrom>2012-10-26</expFrom>
<expTo>2016-11-26</expTo>
</ExperienceRequired>
</JobAd>
<JobAd JobId="2" >
<jobTitle>Programmer</jobTitle>
<jobDescription>Developer</jobDescription>
<QualificationsRequired>
<QLevel>PhD</QLevel>
<QName>Developer</QName>
<QFaculty>IT</QFaculty>
<QUniversity>Azhar Univircity of Gaza</QUniversity>
<QGrade>Excellent</QGrade>
<gradDate>1995-04-19</gradDate>
</QualificationsRequired>
<ExperienceRequired>
<ExpPosition>Programmer</ExpPosition>
<expDescription>Developer</expDescription>
<expEmployer>Pro</expEmployer>
<expFrom>2012-10-26</expFrom>
<expTo>2016-11-26</expTo>
</ExperienceRequired>
</JobAd>
</EmployerJobAds>
</Employer>
<Employer employerId="2">
<EmployerName>Ahmad</EmployerName>
<EmployerAddress>Gaza</EmployerAddress>
<EmployerEmail>ahmad.abuabdou@live.com</EmployerEmail>
<EmployerPhone>0598787121</EmployerPhone>
<EmployerJobAds >
<JobAd JobId="3" >
<jobTitle>Programmer</jobTitle>
<jobDescription>Developer</jobDescription>
<QualificationsRequired>
<QLevel>PhD</QLevel>
<QName>Developer</QName>
<QFaculty>IT</QFaculty>
<QUniversity>Azhar Univircity of Gaza</QUniversity>
<QGrade>Excellent</QGrade>
<gradDate>1995-04-19</gradDate>
</QualificationsRequired>
<ExperienceRequired>
<ExpPosition>Programmer</ExpPosition>
<expDescription>Developer</expDescription>
<expEmployer>Pro</expEmployer>
<expFrom>2012-10-26</expFrom>
<expTo>2016-11-26</expTo>
</ExperienceRequired>
</JobAd>
</EmployerJobAds>
</Employer>
</EmploymnetService>
这是我到目前为止所得到的 enter image description here
答案 0 :(得分:0)
我无法在for-each
中获得EmpID
在<xsl:for-each select="EmploymnetService/Employer/EmployerJobAds/JobAd">
区块中,更改:
<td><xsl:value-of select="@employerId"/></td>
为:
<td><xsl:value-of select="ancestor::Employer/@employerId"/></td>