是否可以构建一个混合的ViewResult,它以AjaxRequest或HttpRequest的顺序返回PartialViewResult
或ViewResult
?
IsAjaxRequest - >返回PartialViewResult !IsAjaxRequest - >返回ViewResult
据我所知,我的HybridViewResult应该来自ViewResultBase。
但是如何实现FindView方法?
答案 0 :(得分:2)
尝试:
public class HybridViewResult : ActionResult
{
public string ViewName { get; set; }
public HybridViewResult () { }
public HybridViewResult (string viewName ) { this.ViewName = viewName ; }
public override void ExecuteResult(ControllerContext context)
{
if (context == null) throw new ArgumentNullException("context");
var usePartial = ShouldUsePartial();
ActionResult res = GetInnerViewResult(usePartial);
res.ExecuteResult(context);
}
private ActionResult GetInnerViewResult(bool usePartial)
{
var view = ViewName;
ActionResult res;
if(String.IsNullOrEmpty(view)) {
res = usePartial ? new PartialViewResult(view) : new ViewResult(view);
}
else {
res = usePartial ? new PartialViewResult() : new ViewResult();
}
return res;
}
private bool ShouldUsePartial(ControllerContext context) {
return false; //your code that checks if you need to use partial here
}
}
添加任何构造函数&根据需要获取GetInnerViewResult变量,即传递Model。
答案 1 :(得分:2)
对于eglasius的答案,这是一个稍微简单的一点。我实际上正在解决类似的问题,除了我需要返回一个JsonResult。
(未经测试的)NormalOrAjaxResult只允许您为非ajax请求指定一个动作结果,为ajax请求指定一个动作结果。因为这些是ActionResults,所以你可以混淆Redirect,View,Partial和Json视图结果。
public class NormalOrAjaxResult : ActionResult
{
private readonly ActionResult _nonAjaxActionResult;
private readonly ActionResult _ajaxActionResult;
public NormalOrAjaxResult(ActionResult nonAjaxActionResult, ActionResult ajaxActionResult)
{
_nonAjaxActionResult = nonAjaxActionResult;
_ajaxActionResult = ajaxActionResult;
}
public override void ExecuteResult(ControllerContext context)
{
var isAjaxRequest = context.HttpContext.Request["isAjax"];
if (isAjaxRequest != null && isAjaxRequest.ToLower() == "true")
{
_ajaxActionResult.ExecuteResult(context);
} else
{
_nonAjaxActionResult.ExecuteResult(context);
}
}
}
答案 2 :(得分:1)
在这种情况下你不能只做两个不同的行动吗?您可以简单地将{共享'逻辑放入[nonAction]
方法?
答案 3 :(得分:1)
我知道我在这里参加派对的时间已经很晚了,但这些对我来说似乎不对,所以这里是我的2美分:
public class PartialViewConverter : ViewResult
{
public ViewResultBase Res { get; set; }
public PartialViewConverter(ViewResultBase res) { Res = res; }
public override void ExecuteResult(ControllerContext context)
{
Res.ExecuteResult(context);
}
public static ViewResult Convert(ViewResultBase res)
{
return new PartialViewConverter(res);
}
}
使用方法:
return PartialViewConverter.Convert(PartialView());
然后在控制器中覆盖View
protected override ViewResult View(string viewName, string masterName, object model)
{
//Whichever condition you like can go here
if (Request.QueryString["partial"] != null)
return PartialViewConverter.Convert(PartialView(viewName, model));
else
return base.View(viewName, masterName, model);
}
您返回视图的任何操作方法都会在请求时自动返回部分内容:
public ActionResult Index()
{
ViewBag.Message = "Modify this template to jump-start your ASP.NET MVC application.";
//This will return a partial if partial=true is passed in the querystring.
return View();
}