我想将3个参数从jquery调用传递给web api方法:
string [] a,string [] b,string [] c。但我不能。
<script type="text/javascript">
function fncsave() {
var arrtemplate = [];
var arrrole = [];
var arrpcode = [];
$('#mytemplateTags li').each(function () {
var str = $(this).html();
var res = str.match("<span class=\"tagit-label\">(.*?)</span>");
if (res!=null) {
var str = res[1];
arrtemplate.push(str);
}
});
$('#myroleTags li').each(function () {
var str = $(this).html();
var res = str.match("<span class=\"tagit-label\">(.*?)</span>");
if (res != null) {
var str = res[1];
arrrole.push(str);
}
});
$('#myprocessCodeTags li').each(function () {
var str = $(this).html();
var res = str.match("<span class=\"tagit-label\">(.*?)</span>");
if (res != null) {
var str = res[1];
arrpcode.push(str);
}
});
console.log(JSON.stringify(arrtemplate));
$.ajax({
url: "/api/TagCloud/SessionTemplate",
method: "Post",
data:JSON.stringify( { templates : arrtemplate, roles : arrrole, pcodes : arrpcode}),
async: false,
contentType: 'application/json; charset=utf-8',
dataType: "json",
success: function (msg) {
console.log(msg);
if (msg == true) {
// alert("true");
}
}
});
}
</script>
C#代码:
[HttpPost]
public bool SessionTemplate(string[] templates, string[] roles, string[] pcodes)
{
HttpContext.Current.Session["templates"] = templates;
HttpContext.Current.Session["roles"] = roles;
HttpContext.Current.Session["pcodes"] = pcodes;
return true;
}
答案 0 :(得分:1)
将字符串数组添加到新数组中,如下所示:
//the nested array (hardcoded for clarity)
var newarray = {a:['a','b','c'],b:['d','e','f']a:['g','h','i']};
var jsondata = JSON.stringify(newarray);
//send jsondata to server
然后使用JavaScriptSerializer class:
反序列化服务器端的json数据//assign submitted json to the variable jsondata (hardcoded for clarity)
String jsondata = "{a:['a','b','c'],b:['d','e','f']a:['g','h','i']}";
JavaScriptSerializer jsonparser = new JavaScriptSerializer();
dynamic result = jsonparser.Deserialize<dynamic>(jsondata);
Respone.Write(result['a',2]); //writes 'c'
如果您没有类别,则可以使用dynamic result = jsonparser.Deserialize<dynamic>(jsondata);
。
当您这样做时,您可以使用MyClass result = jsonparser.Deserialize(jsondata,MyClass);
使用对象初始值设定项自动分配值返回一个用值填充的类的新实例。