将内存分配给**

Question

我有这个结构

typedef struct{
 char **palavras;
}no;

我想基本上为这个字符串数组分配内存

而且我无法做到这一点，因为它表示它会在＆＃39;之前预期一些事情（＆＃39;

no *atual;

atual->(*palavras)=calloc(1,sizeof(char*));

Answer 1

您需要分几个阶段完成：

• 首先，将内存分配给atual，
• 接下来，将内存分配给palavras
• 最后，将内存分配给palavras
的元素

假设你需要分配10 palavras，你可以这样做：

no *atual = malloc(sizeof(no));
atual->palavras = malloc(sizeof(char*)*10);
atual->palavras[0] = malloc(20);
...

Answer 2

您应该palavras访问atual->palavras，例如atual->palavras = calloc(5, sizeof(char *))，char ** *atual->palavras取消引用char *。您也可以atual->palavras为atual->palavras[0] = malloc(10 * sizeof(char))指针分配内存，例如# To remove trailing slash RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME} !-d RewriteRule ^(.*)/$ $1 [R=301,L] # To remove .php extension RewriteRule ^(.*)\.php$ $1 [R=301,L] # To check whether the file exists then set it back internally RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME} !-f RewriteCond %{DOCUMENT_ROOT}%{REQUEST_FILENAME}.php -f RewriteRule ^.*$ $0.php [L] 。