我对此代码有疑问:
if($sql = $this->database->query("SELECT * FROM warenkorb_artikel WHERE WarenkorbID = '".$erg['WarenkorbID']."'"))
{
while($erg = $sql->fetch_assoc())
{
[...]
}
}
我收到错误:
致命错误:在非对象上调用成员函数fetch_assoc() 在[...]中,“while($ eg = $ sql-> fetch_assoc())”是。
任何人都可以帮助我吗?
答案 0 :(得分:0)
您需要分解,以便捕获您在mysqli
API返回的查询中所犯的任何错误。
$sql = "SELECT *
FROM warenkorb_artikel
WHERE WarenkorbID = '{$erg['WarenkorbID']}'";
$result = $this->database->query($sql);
if ( $result === false ) {
echo $this->database->error;
exit;
}
// do you really need a while loop, as it look like you might be
// selecting a row using a unique key?
while($row = $result->fetch_assoc()){
[...]
}