Question

这会产生语法错误：

import numpy as np
import scipy.interpolate
import matplotlib.pyplot as plt
y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198])
x = np.array(range(len(y)))
stepsize = 0.0001
xvals = np.arange(0,13.0001,stepsize)
func = scipy.interpolate.interp1d(x, y, kind = "cubic")
yvals = func(xvals)
plt.plot(xvals,yvals)
plt.plot(x,y, "o")
dif = np.diff(yvals)
for i in range(len(y))
    if i == 0:
        print dif[int(i*1/stepsize)]
    else:
        print dif[int(i*1/stepsize)-1]

它在第5行中给出了语法错误，如此

y = np.array（[ - 0.23122875，-0.11375591，-0.09760733，-0.07401004，-0.03565704，-0.02449268，-0.01411058,0.0018971，-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349， 0.02707902,0.01996198]） ^ SyntaxError：语法无效

我只是不知道为什么。当我更改y中的某些值时，它会突然发挥作用。

提前致谢

Answer 1

您似乎在此行中使用了soft hyphen：

y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198])

您需要将其切换为hyphen-minus，如下所示：

y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198])

为什么我在以下代码中出现语法错误

1 个答案: