我尝试编写此代码将温度从华氏温度转换为摄氏温度,反之亦然。
try:
temperature=raw_input ("Enter temperature in numerals only")
temp1=float(temperature)
conversion=raw_input ("Convert to (F)ahrenheit or (C)elsius?")
def celtofah():
temp2 = (9/5)*temp1+32
print temp1," C = ",temp2," F"
def fahtocel():
temp2 = (5/9)*(temp1-32)
print temp1," F = ",temp2," C"
if conversion == F:
celtofah()
elif conversion == C:
fahtocel()
except:
print "Please enter a numeric value"
但是我似乎在第5行得到了错误,我已经定义了celtofah函数。
我不认为缩进在这里是错误的,虽然我可能会错过任何东西。
答案 0 :(得分:4)
这是你的缩进,即使没有看你的形象。 为了使它工作,您可以简单地缩进所有def和if / elif。 但更好的是,如果你在try / except之前定义那些函数,转换和if之后的else中的if / elif和除了ValueError之外的except更改。你也应该使用函数的参数,你使用的F和C是未声明的变量。
def celtofah(temp1):
temp2 = (9/5)*temp1+32
print temp1," C = ",temp2," F"
def fahtocel(temp1):
temp2 = (5/9)*(temp1-32)
print temp1," F = ",temp2," C"
try:
temperature=raw_input ("Enter temperature in numerals only")
temp1=float(temperature)
except ValueError:
print "Please enter a numeric value"
else:
conversion=raw_input ("Convert to (F)ahrenheit or (C)elsius?")
if conversion == 'F':
celtofah(temp1)
elif conversion == 'C':
fahtocel(temp1)
还有一些其他的事情你可以改进你的代码,也许我错过了,但这可以作为模板。
答案 1 :(得分:3)
问题是try / except缩进,如果比较(C和F应该是字符串):
try:
temperature = raw_input("Enter temperature in numerals only")
temp1 = float(temperature)
conversion = raw_input("Convert to (F)ahrenheit or (C)elsius?")
def celtofah():
temp2 = (9 / 5) * temp1 + 32
print temp1, " C = ", temp2, " F"
def fahtocel():
temp2 = (5 / 9) * (temp1 - 32)
print temp1, " F = ", temp2, " C"
if conversion == "F":
celtofah()
elif conversion == "C":
fahtocel()
except:
print "Please enter a numeric value"