我有一个图表,每个节点与其子节点具有父关系(如附图所示)和一个名称属性。 我想在嵌套的json对象中显示这个图,如下所示:
{name: A,
children: [{name: A1,
children: A11, A12, A13 },
{name: A2,
children: A21, A22, A23},
{name: A3,
children: A31, A32, A33}
]}
我想遍历任何深度,所以关系应该是(a) - [*] - >(b)。 参考this question,我想出了以下查询:
match(parent{name: "A"})-[*]->(child)
with parent, child, collect(child.name) as children
return {name: parent.name,
children: collect({name: child.name,
children: children})}
但上述查询会产生以下结果:
name A
children [
name A23
children [A23]
,
name A22
children [A22]
,
name A32
children [A32]
,
name A2
children [A2]
,
name A12
children [A12]
,
name A21
children [A21]
,
name A31
children [A31]
,
name A1
children [A1]
,
name A11
children [A11]
,
name A33
children [A33]
,
name A3
children [A3]
,
name A13
children [A13]
]
那么,如上所述,以json对象的形式表示这个完整树的可能解决方案是什么?
答案 0 :(得分:1)
我向APOC添加了这样的功能,请随时查看: https://github.com/neo4j-contrib/neo4j-apoc-procedures#fromtojson
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