Question

我不熟悉Android Studio上的HttpUrlConnection。我尝试在Eclipse中使用HttpClient进行编码，它可以工作。 HttpClient现在已在Android Studio中弃用，因此我尝试使用HttpUrlConnection进行更改。我在Android Studio中的代码是这样的：

public String LedOff(View view) {
    try {
        URL url = new URL("http://192.168.4.1/LEDOff");
        HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
        urlConnection.connect();
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

}

Eclipse中的

是这样的：

public void LedOff (View view){

        String url = "http://192.168.4.1/LEDOff";

        HttpClient httpClient = new DefaultHttpClient();

        try {
            httpClient.execute(new HttpGet(url));
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
}

我不知道什么是错的。请帮帮我。感谢。

Answer 1

确保您的Manifest中有这两个权限：

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

修改
添加了LedOff()方法的代码，将成功的响应视为String。

按照Android Docs尝试此操作：

public String LedOff(View view) { try { URL url = new URL("http://192.168.4.1/LEDOff"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setReadTimeout(10000 /* milliseconds */); conn.setConnectTimeout(15000 /* milliseconds */); conn.setRequestMethod("GET"); // Or any method you need conn.setDoInput(true); // Starts the query conn.connect(); int response = conn.getResponseCode(); Log.d(DEBUG_TAG, "The response code is: " + response); if ((response >= 200) && (response < 300)) { // We are assuming here that whatever the response is, it can be parsed as a String Log.d(DEBUG_TAG, "The response is: " + conn.getResponseMessage()); } } catch(Exception ex) { // Handle any exceptions } }

Answer 2

您必须通过调用getInputStream()，getResponseCode()或getResponseMessage()来提交请求，以便返回和处理回复。

Connect()方法只是创建连接。

检查：

Log.i("Response Code" , urlConnection .getResponseCode());

看看你得到了什么回应。

Answer 3

试试这个

var tsProject = ts.createProject(paths.typescriptRoot + 'tsConfig.json'); // use tsconfig.json
    gulp.task("tsbuild", function () {
        var tsResult = tsProject.src()
            .pipe(sourcemaps.init()) // needed to create sourcemaps
            .pipe(ts(tsProject)); // use tsconfig.json
        return tsResult.js
            .pipe(concat(paths.concatTsFileName)) // concat all output files into a sings js files
            .pipe(sourcemaps.write()) // write the sourcemap to be able to debug the ts files
            .pipe(gulp.dest(paths.typescriptOut)); // output the result on specific path
    });

Android中的HttpUrlConnection没有错误但无法正常工作

3 个答案: