我创建了一个简单的html表单来测试,我如何在wpdb中插入数据。我知道如何在PHP中实现它,但在wordpress中我感到困惑!
global $wpdb;
if (isset($_POST['submit'])) {
$name = $_POST['r1s1']; //Here r1s1 is name of the form control
$email = $_POST['r2s1'];
$contact = $_POST['r3s1'];
$address = $_POST['r5s1'];
if ($name != '' || $email != '') {
$post = $wpdb->insert(
'table', array(
'feild' => $name,
'dev' => $email,
'tenant' => $contact,
'mod' => $address,
), array(
'%s',
'%s',
'%s',
'%s'
)
);
echo $post;
if ($post) {
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
} else {
echo "<br/><br/><span>Insertion Failed...!!</span>";
}
} else {
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}
当我点击提交按钮时,它会显示消息insertion failed...!!
(我通过回信打印的消息)。此代码是用模板编写的。我做错了什么?
答案 0 :(得分:2)
HttpURLConnection
试试这个
答案 1 :(得分:1)
您可以尝试以下代码吗?
global $wpdb;
$table_name = $wpdb->prefix . "your_table_name";
if (isset($_POST['submit'])) {
$name = $_POST['r1s1']; //Here r1s1 is name of the form control
$email = $_POST['r2s1'];
$contact = $_POST['r3s1'];
$address = $_POST['r5s1'];
$data = array(
'feild' => $name,
'dev' => $email,
'tenant' => $contact,
'mod' => $address
);
if ($name != '' || $email != '') {
$result = $wpdb->insert($table_name, $data);
if ($result) {
echo "<br/><br/><span>Data Inserted successfully...!!</span>";
} else {
echo "<br/><br/><span>Insertion Failed...!!</span>";
}
} else {
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}