Question

我将数据从服务器发送到android并且我在数据库中有一个字段作为时间戳，我也发送数据作为JSON但是当我发送数据时它显示的日期如下：date“：1463232118”或者当我从它显示日期的代码中删除'strtotime'函数，如下所示：2016-05-18 10:24:32但是当我把'strtotime'放在将要发送到android端的JSON数组时，我打开它浏览器它显示如下：4周前或3天前它是正确的但当我发送它作为JSON数组时它显示：日期“：1463232118”。这是我完整的PHP代码指南，或者添加你知道的东西

<?php

require_once("include.php");

$tbl_name ="ads";
$order_by ="id";

$records_limit= 6;


$connect = @mysqli_connect($hostname , $username , $password , $database);

if( $connect )
{
    @mysqli_query($connect , "SET CHARACTER SET utf8;");

    $temp1 = @mysqli_query($connect , "SELECT COUNT (*) FROM".$tbl_name);

    $temp2 = @mysqli_fetch_row($temp1);

    $total_records = $temp2[0];

    if(isset( $_GET['page']))
    {
        $page = $_GET['page'];
        $offset = $page * $records_limit;
    }
    else
    {
        $page = 0;
        $offset = 0;
    }

    $my_query = "SELECT * FROM ".$tbl_name." ORDER BY ".$order_by." DESC LIMIT ".$offset.",".$records_limit;

    $result = @mysqli_query($connect , $my_query);
    if( $result )
    {
        $response['ads'] = array();
        $response['success'] = 1;  


        while( $row = @mysqli_fetch_array($result) )
        {
            $ads = array();

            $curenttime=$row['date'];
            $time_ago =strtotime($curenttime);

            $ads['id']  = $row['id'];
            $ads['title']   = $row['title'];    
            $ads['intro']   = $row['intro'];
                    $ads['image']   = $sitename . $row['image'];
            $ads['seller']  = $row['seller'];
            $ads['phone']   = $row['phone'];

            $ads['date']    = $time_ago;

            $q = "SELECT name FROM cat WHERE id='".$row['cat_id']."'";
            $temp1 = @mysqli_query($connect , $q);
            $temp2 = @mysqli_fetch_row($temp1);
            $cat = $temp2[0];


            $ads['cat'] = $cat;         

            array_push( $response['ads'] , $ads);
        }
    }
    else
    {
        $response['success'] = 0;
        $response['message'] = "nothing";
    }

    echo(json_encode($response)); 


    @mysqli_close( $connect );
}



function timeAgo($time_ago){

$cur_time   = time();
$time_elapsed   = $cur_time - $time_ago;
$seconds    = $time_elapsed ;
$minutes    = round($time_elapsed / 60 );
$hours      = round($time_elapsed / 3600);
$days       = round($time_elapsed / 86400 );
$weeks      = round($time_elapsed / 604800);
$months     = round($time_elapsed / 2600640 );
$years      = round($time_elapsed / 31207680 );
// Seconds
if($seconds <= 60){
    echo "$seconds seconds ago";
}
//Minutes
else if($minutes <=60){
    if($minutes==1){
        echo "one minute ago";
    }
    else{
        echo "$minutes minutes ago";
    }
}
//Hours
else if($hours <=24){
    if($hours==1){
        echo "an hour ago";
    }else{
        echo "$hours hours ago";
    }
}
//Days
else if($days <= 7){
    if($days==1){
        echo "yesterday";
    }else{
        echo "$days days ago";
    }
}
//Weeks
else if($weeks <= 4.3){
    if($weeks==1){
        echo "a week ago";
    }else{
        echo "$weeks weeks ago";
    }
}
//Months
else if($months <=12){
    if($months==1){
        echo "a month ago";
    }else{
        echo "$months months ago";
    }
}
//Years
else{
    if($years==1){
        echo "one year ago";
    }else{
        echo "$years years ago";
    }
}
}

?>

以下是我将$curenttime=$ads['date']; $time_ago =strtotime($curenttime); echo timeAgo($time_ago);放在数组外的输出。

  5 hours ago5 hours ago4 days ago4 days ago4 days ago

Answer 1

timeAgo函数应return值，而不是echo。

你忘了给$ads['date'] = timeAgo($time_ago);打电话，这就是为什么你的JSON中有strtotime值而不是之前的转换值。

修改

要从timeAgo()函数返回值，只需执行以下操作：

return $seconds . " seconds ago";

在PHP和Android中将TimeStamp转换为可读时间

1 个答案: