Question

我是java的新手，虽然我正在为坐着的计划编码，但counsole一直给我错误请帮助＆gt;。＆lt;

这是SittingPlan的课程

public SittingPlan()
{
    String[] name = {"charles" };
    String[] sex = {" Girl", "Boy"};
    Students[] names = new Students[NUMBER_OF_STUDENTS];
    currentStudents = 0;
    for ( int count = 0; count < names.length; count++ )
        names [ count ] = new Students ( name [count % 22 ], sex [ count / 22 ]);
}
public void shuffle()
{
    currentStudents = 0;
    SittingPlan.shuffle.setName();
    for ( int first = 0; first < names.length; first++ )
    { 
        int second = randomNumbers.nextInt ( NUMBER_OF_STUDENTS );
        Students temp = names[ first ];
        names[ first ] = names[ second ];
        names[ second ] = (Students) temp;
    }

}
public Students dealStudents()
{
    if ( currentStudents < names.length )
        return (Students) names[ currentStudents++ ];
    else
        return null;
}

这是堆栈跟踪

线程中的异常＆＃34; main＆＃34; java.lang.Error：未解决的编译问题： shuffle无法解析或不是字段

at SittingPlan.shuffle(SittingPlan.java:22)
at mainlaunch.main(mainlaunch.java:6)

Answer 1

这一行错了：

SittingPlan.shuffle.setName();

shuffle()是一种方法，但它不是static。它返回void，因此您无法在返回值上调用setName()。

我猜不出你想要什么。这段代码令人困惑。

我认为更好的想法是使用Java集合，如下所示：

List<Student> classList = new ArrayList<Student>();
// populate with Student instances
Random random = new Random(seed);
Collections.shuffle(classList, random);

对象无法解析或不是字段

1 个答案: