按特定条件从字典列表中删除重复项

Question

我想通过id删除重复元素，其中status == a。

我的计划：

1. 输入列表 - list1
2. 从list1
创建所有ID的list2
3. 从list2
创建重复项ID列表3
4. 从原始list1元素中删除list3中的id和where =='a'

所以我写了这段代码：

# Create list2 of all ids
def get_list_of_all_ids(lst):
    ids = []
    for i in lst:
        for x in i:
            if x == 'id':
                ids.append(i['id'])
    return ids    

# Create list3 of duplicates ids
def get_list_of_duplicates_ids(lst):
    return list(set([x for x in lst if lst.count(x) >= 2]))

# Remove from origin list elements where id in list3 and where status == 'a'
def remove_duplicates(lst_of_dcts, lst_of_ids):
    new_list = lst_of_dcts
    for i in lst_of_dcts:
            if i['id'] in lst_of_ids and i['status'] == 'a':
                new_list.remove(i)
    return new_list, len(new_list)

def go(list_of_dicts):
    return remove_duplicates(
        list_of_dicts, get_list_of_duplicates_ids(
            get_list_of_all_ids(
                list_of_dicts)
        )
    )

print(go(lst))

输入：

lst = [{'id': 2, 'status': 'a'},
{'id': 1, 'status': 'a'},
{'id': 4, 'status': 'z'},
{'id': 2, 'status': 'c'},
{'id': 3, 'status': 'a'},
{'id': 1, 'status': 'b'},
{'id': 5, 'status': 'a'},
{'id': 0, 'status': 'g'},
{'id': 5, 'status': 'f'}]

我的期望：

([{'status':'z','id':4},
{'status':'c','id':2},
{'status':'a','id':3},
{'status':'b','id':1},
{'status':'g','id':0},
{'status':'f','id':5}], 6)

我得到了什么：

([{'status':'a','id':1},
{'status':'z','id':4},
{'status':'c','id':2},
{'status':'a','id':3},
{'status':'b','id':1},
{'status':'g','id':0},
{'status':'f','id':5}], 7)