Question

我从这个社区获得了很多帮助，让我的时间表报告正常工作。设置方式是通过检查ajax返回来获取日期范围。然后它会按照一周中的哪一天将所有参赛作品分组。如果特定的i日期范围没有条目，那么它只会返回＆＃34;今天没有条目。＆＃34;

远一切正常，您可以看到以下示例： https://jsfiddle.net/j3yg2j7j/7/

但是我注意到如果日期范围中的最后一天为空，则忽略它。我需要它返回＆＃34;今天没有条目。＆＃34;即使最后一天是空的。

以下是此问题的示例。 https://jsfiddle.net/j3yg2j7j/6/

更新：发现另一个奇怪的问题。当我给它2016-05-02到2016-05-05的范围。我开始收到重复的项目。

这是Ajax请求：

responseText: {
    d: {
        results: [{
            ID: "1",
            Description: "Test1",
            Date: "2016-05-02 09:45"
        }, {
            ID: "2",
            Description: "Test2",
            Date: "2016-05-02 10:45"
        }, {
            ID: "3",
            Description: "Test3",
            Date: "2016-05-03 11:45"
        }, {
            ID: "4",
            Description: "Test4",
            Date: "2016-05-03 11:45",
        }]
    }
}

这是javascript：

      var items_by_date  = {}; // declare an object that will have date indexes
      $.ajax({url:"/SomeUrlBeginninWithSlash",
          dataType: 'json',
          cache: false,
          success: function (data) {
                    console.log("SUCCESS",data);    
                    drawTable(data.d.results);
          }
      });

 var drawTable = function(data) {
  // First sort the entries by date:
  data = data.sort(function(a, b) {
    return (moment(a.Date) - moment(b.Date));
  });

  // Find the date range to work with by looking at each end of the array:
  var firstDate = moment("2016-05-02");
  var lastDate = moment("2016-05-04");

  // loop through each day in that range, keeping track of a starting point i
  // so we don't have to keep checking already-passed events.
  var i = 0, // pointer to the first entry to check on the next date
    ret = ""; 
  for (var thisDate = firstDate; thisDate <= lastDate; thisDate.add(1, 'days')) {
    ret += '<tr><th>' + thisDate.format("dddd, MMMM D") + "</th></tr>";

    // check to see if the next entry is already beyond thisDate:
    if (moment(data[i].Date) > thisDate.endOf('day')) {
      ret += "<tr><td>No entries today.</td></tr>";
    } else {
      // starting at entry i, display all entries before the end of thisDate:
      for (var j = i; j < data.length; j++) {
        if (moment(data[j].Date) < thisDate.endOf('day')) {
          // the next one belongs on thisDate, so display it:
          ret += '<tr><td>' + moment(data[j].Date).format("HH:mm") + " - " + data[j].Description + "</td></tr>";
        } else {
          // next one is not for thisDate, so we can go on to the next day.
          i = j; // It'll start here, so we don't waste time looping over past events
          break; // (out of the inner loop)
        }
      }
    }
  }
  $('#x').html(ret);
}

我知道我忽略了一些简单但却无法用手指指着它。

Answer 1

对于缺席的最后一天，您将lastDate设置为5月4日 - 它需要在当天结束时代替：

var lastDate = moment("2016-05-04").endOf('day');

重复的事件是因为我为你的上一个问题写的代码假设条目列表中的最后一个日期是你想要显示的最后日期，所以它不需要处理你的情况在用完条目后继续循环执行日期。这可以通过处理这种情况来解决：

if (i === data.length) {
   // we've run out of entries; don't try to check past the end of the data array:
   ret += "<tr><td>No entries today.</td></tr>";   
} else if (moment(data[i].Date) > thisDate.endOf('day')) {
  // The next entry is later than this day.
  ret += "<tr><td>No entries today.</td></tr>";
} else {
  // starting at entry i, display all entries before the end of thisDate:
  for (var j = i; j < data.length; j++) {
    if (moment(data[j].Date) < thisDate.endOf('day')) {
      // the next one belongs on thisDate, so display it:
      ret += '<tr><td>' + moment(data[j].Date).format("HH:mm") + " - " + data[j].Description + "</td></tr>";
    } else {
      // next one is not for thisDate, so we can go on to the next day.
      i = j; // It'll start here, so we don't waste time looping over past events
      break; // (out of the inner loop)
    }
  }
  // Did we run out of entries?  If so, need to update i here to prevent repeated display
  if (j === data.length) {
    i = j;
  }
}

https://jsfiddle.net/tt35rnoo/

然而...

考虑到您在此问题上提出变体的次数，最好在此处保持简单。尝试这种效率较低但复杂程度较低的版本，它不会尝试跳过每个循环上已经显示的事件：

  // loop through each day in that range
  var ret = ""; 
  for (var thisDate = firstDate; thisDate <= lastDate; thisDate.add(1, 'days')) {
    ret += '<tr><th>' + thisDate.format("dddd, MMMM D") + "</th></tr>";
    var showedAnEventToday=false;

    for (var j = 0; j < data.length; j++) {
        if (
            moment(data[j].Date) > thisDate.startOf('day') && 
            moment(data[j].Date) < thisDate.endOf('day')
        ) {

          showedAnEventToday = true;
          ret += '<tr><td>' + moment(data[j].Date).format("HH:mm") + " - " + data[j].Description + "</td></tr>";
        } 
    }
    if (!showedAnEventToday) {
        ret += '<tr><td>No events today.</td></tr>';
    }
  }
  $('#x').html(ret);

https://jsfiddle.net/ejaca00t/

Moment / Jquery - 简单时间表的愚蠢问题

1 个答案:

然而...