Question

我第一次使用Joomla，我必须编写一些外部PHP代码来更新joomla数据库。这是我的代码

<?php

  define( '_JEXEC', 1 );
  define( 'DS', DIRECTORY_SEPARATOR );
  define( 'JPATH_BASE', $_SERVER[ 'DOCUMENT_ROOT' ] );
   // my project directory name is Joomla
  require_once( JPATH_BASE .DS.'Joomla'.DS . 'libraries' . DS . 'joomla' . DS . 'factory.php' );

  $db = JFactory::getDBO();
  $query = $db->getQuery(true);
  $fields = array(
  $db->quoteName('title') . ' = ' . $db->quote('Menu Updated'));
  $conditions = array(
  $db->quoteName('id') . ' = 103' );
  $query->update($db->quoteName('iqogr_menu'))->set($fields)->where($conditions);
  $db->setQuery($query);
  $result = $db->loadResult();

?>

现在我在JFactory :: getDBO（）中遇到问题;这条线什么都没有，没有任何错误，在该行之后的任何事情都没有执行甚至不回应。

Answer 1

要在Joomla之外调用Joomla类，您可以使用此代码

$dir = '/var/www/Joomla'; // path to your joomla installation directory

define( '_JEXEC', 1 );
define( 'JPATH_BASE', $dir);
define( 'DS', '/' );

require_once ( JPATH_BASE .DS . 'configuration.php' );
require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' );
require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' );

require_once ( JPATH_BASE .DS.'libraries'.DS.'joomla'.DS.'factory.php' );
//Then you can call the classes this way
$mainframe = JFactory::getApplication('site');
$db = JFactory::getDBO();

Answer 2

这对我有用：

define( '_JEXEC', 1); 

define( 'DS', DIRECTORY_SEPARATOR );
define( 'JPATH_BASE', realpath(dirname(__FILE__) .'/' ) );

require_once ( JPATH_BASE . '/includes/defines.php' );
require_once ( JPATH_BASE . '/includes/framework.php' );

$db         = JFactory::getDbo();
$query      = $db->getQuery(true);

放在根目录中。

Joomla 3.5.1 JFactory :: getDBO（）;不工作，不抛错误

2 个答案: