Question

我有两个对象，我需要根据另一个对象的属性匹配向一个对象添加属性：

"visible":false,
"type": 'hidden',

我想补充一下：

tableCols

到data对象dependsOn属性与public class MainActivity extends AppCompatActivity { private LinearLayoutManager linearLayoutManager; private Adapter adap; private EditText dialogButton; private Context context =this; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); RecyclerView rv = (RecyclerView) findViewById(R.id.recycler_view); rv.setHasFixedSize(true); linearLayoutManager = new LinearLayoutManager(this); rv.setLayoutManager(linearLayoutManager); List<Students> list = getListItemData(); adap = new Adapter(getApplicationContext(), list); rv.setAdapter(adap); dialogButton = (EditText) findViewById(R.id.et_amount); dialogButton.setOnClickListener(new View.OnClickListener(){ @Override public void onClick(View v) { final android.app.AlertDialog.Builder inputAlert = new android.app.AlertDialog.Builder(context); inputAlert.setTitle("Title of the Input Box"); inputAlert.setMessage("We need your name to proceed"); final EditText userInput = new EditText(context); inputAlert.setView(userInput); inputAlert.setPositiveButton("Submit", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { String userInputValue = userInput.getText().toString(); EditText et=(EditText)findViewById(R.id.et_amount); et.setText(userInputValue); } }); inputAlert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.dismiss(); } }); android.app.AlertDialog alertDialog = inputAlert.create(); alertDialog.show(); } }); } public List<Students> getListItemData(){ List<Students> listItem = new ArrayList<Students>(); listItem.add(new Students("Prashant Dhimal",850)); listItem.add(new Students("Prashanta",850)); listItem.add(new Students("Pratistha",850)); listItem.add(new Students("Prince",850)); listItem.add(new Students("Ranjan",850)); listItem.add(new Students("Rabi Tiwari",850)); listItem.add(new Students("Rajan ",850)); listItem.add(new Students("Rahul",850)); listItem.add(new Students("Rachana",850)); listItem.add(new Students("Ravi karki",850)); listItem.add(new Students("Raisha",850)); listItem.add(new Students("Rashmi",850)); listItem.add(new Students("Rinku",850)); listItem.add(new Students("Rajat",850)); listItem.add(new Students("Rabin",850)); listItem.add(new Students("Ramesh",850)); listItem.add(new Students("Ragbendra",850)); listItem.add(new Students("Subash Gautam",850)); listItem.add(new Students("Subash Gc",850)); listItem.add(new Students("Subash Parajuli",850)); listItem.add(new Students("Sudip bajgai",850)); listItem.add(new Students("Suman Thapa",850)); listItem.add(new Students("Suman Shrestha",850)); listItem.add(new Students("Saurav Man Pradhan",850)); listItem.add(new Students("Saurav Karn",850)); listItem.add(new Students("Shruti",850)); listItem.add(new Students("Swagat Gaire",850)); listItem.add(new Students("Swagat Ranjit",850)); listItem.add(new Students("Swikriti ",850)); listItem.add(new Students("Udin",850)); listItem.add(new Students("Ujwal",850)); listItem.add(new Students("Yunisha",850)); listItem.add(new Students("Sahan",850)); listItem.add(new Students("Samyukta",850)); listItem.add(new Students("Sanjay Koju",850)); listItem.add(new Students("Sanjay Thapa",850)); listItem.add(new Students("Srizan",850)); listItem.add(new Students("Ram",850)); listItem.add(new Students("Susovik",850)); listItem.add(new Students("Suraj",850)); listItem.add(new Students("Ujwal",850)); listItem.add(new Students("Sital",850)); listItem.add(new Students("Siddharth",850)); listItem.add(new Students("Sagar",850)); listItem.add(new Students("Sudarshan",850)); return listItem; } }中的属性匹配。

https://jsfiddle.net/zwpu70no/3/

Answer 1

使用Object.keys和Array.indexOf函数的解决方案：

var dependsOn = {
        qTableIdent: {'RHID': 'RHID', 'SEQ': 'NOME'},
        qTableDocs: {'RHID': 'RHID', 'DOC': 'DOC2'}
    },
    tableCols = [
        {
            "targets": 1,
            "title": 'RHID',
            "label": 'RHID',
            "data": 'RHID',
            "name": 'RHID',
            "width": "5%",
            "filter": true,
            "defaultContent": "",
            attr: {'name': 'rhid'}
        }
    ],
    newProps = {"visible": false, "type": 'hidden'},  // new properties to insert
    dataKeys = [];

Object.keys(dependsOn).forEach(function(k) {
    Object.keys(dependsOn[k]).forEach(function(key) {
        if (dataKeys.indexOf(key) === -1) {
            dataKeys.push(key);
        }
    });
});
// dataKeys now contains unique keys list: ["RHID", "SEQ", "DOC"]

tableCols.forEach(function(obj) {
    if (dataKeys.indexOf(obj['data']) !== -1) {
    Object.keys(this).forEach((k) => obj[k] = this[k]);
    }
}, newProps);

console.log(JSON.stringify(tableCols, 0, 4));    

console.log(JSON.stringify(tableCols, 0 , 4));

'tableCols'数组中单个对象的输出示例：

[
    {
        "targets": 1,
        "title": "RHID",
        "label": "RHID",
        "data": "RHID",
        "name": "RHID",
        "width": "5%",
        "filter": true,
        "defaultContent": "",
        "attr": {
            "name": "rhid"
        },
        "visible": false,
        "type": "hidden"
    }
]

如果属性存在于使用lodash的另一个对象中，则将属性添加到对象

1 个答案: