Question

我已经创建了请求，当我收到成功消息时我想要popView。这是我的代码：

NSURLSession *session = [NSURLSession sharedSession];
NSString *baseURLRequest = [NSString stringWithFormat:@"%@/email_addr=%@",mySession.baseURL,self.txtEmail.text];
NSURLSessionDataTask *dataTask = [session dataTaskWithURL:[NSURL URLWithString:baseURLRequest] completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {

NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
    NSDictionary *dict = [json objectForKey:@"result"];
    NSString *msg = [dict objectForKey:@"msg"];

        if ([[dict objectForKey:@"status"] isEqualToString:@"success"])
        {
            dispatch_async(dispatch_get_main_queue(), ^{
                [self showMesssgeonAlert:@"Success"];
                [self hideProgress];

                [self.navigationController popViewControllerAnimated:YES];
            });
        }
        else
        {
        }
}];
[dataTask resume];

以下不起作用，

[self.navigationController popViewControllerAnimated:YES];

有谁知道为什么会这样？ UINavigation controller的{{1}}也相同。请帮帮我，谢谢。

Answer 1

@DevTest你不能把[self.navigationController popViewControllerAnimated：YES];在dispath队列内部，队列不会弹出viewcontroller所以，你会设置side dispatch queue ...

popViewController在iOS中的NSURLSessionDataTask块中不起作用

1 个答案: