Question

您好我正在尝试使用单独的给定文件中的现有json数据创建更新函数：

people.json：

[{
"firstname": "Smith",
"surname":   "Johnson"
}, {
"firstname": "Sabrina",
"surname":   "Khalifa"
}, {
"firstname": "Joe",
"surname":   "Higgins"
}]

显示功能有效，只需获取上述所有数据。

 public function display() {
    $data = $this->container->get('data');
    $people = $data->load('people');
    $this->render('people', ['people' => $people]);
}

像load这样的容器和方法在其他类中定义。我想抓住＆＃34;名字＆＃34;和＆＃34;姓氏＆＃34;和更新，我明显做了很多错事，但它不会更新：

PeopleController.php：

public function update() {
    $data = $this->container->get('data');
    $people = $data->load('people');
    $this->save('people', ['people' => $people]);
}

的index.php：

 $app->get('/',  'App\\PeopleController:display'); //get all people
 $app->put('/',  'App\\PeopleController:update'); //trying to update

正在使用的HTML：

<form>
<table>
    <tr>
        <th>First name</th>
        <th>Last name</th>
    </tr>
    {% for person in people %} 
    <tr>
        <td><input type="text" name="people[][firstname]" value="{{ person.firstname }}" /></td>
        <td><input type="text" name="people[][surname]" value="{{ person.surname }}" /></td>
    </tr>
    {% endfor %}
</table>
<input type="submit" value="OK" /> 
</form>

的DataLoader：

class DataLoader {

protected $path;

public function __construct($path) {
    $this->path = $path;
}

/**
 * Load data from the requested file
 *
 * @param string $file Filename
 * @return array Decoded file contents
 */
public function load($file) {
    $path = $this->getPath($file);

    if (file_exists($path)) {
        return json_decode(file_get_contents($path), true);
    }

    return [];
}

/**
 * Save data to the requested file
 *
 * @param string $file Filename
 * @param array  $data Contents to save to file
 */
public function save($file, array $data) {
    file_put_contents(json_encode($this->getPath($file)), $data);
}

protected function getPath($file) {
    return $this->path . "/$file.json";
}
}

使用php和slim更新JSON文件

0 个答案: