Question

我有两个对象数组，如下所示：

var array1 = [{"id": "-1","OwnerID": 777,"Admin": "true"},{"id": "-1","OwnerID": 555,"Admin": "true"},{"id": "-1","OwnerID": 444,"Admin": "true"},{"id": "-1","OwnerID": 222,"Admin": "true"},{"id": "-1","OwnerID": 111,"Admin": "true"}];

var array2 = [{"id": 777, "OwnerName": "Blah", "OwnerType": "Test"},{"id": 555, "OwnerName": "Blah", "OwnerType": "Test"},{"id": 444, "OwnerName": "Blah", "OwnerType": "BusinessMan"},{"id": 222, "OwnerName": "Blah", "OwnerType": "BusinessMan"},{"id": 111, "OwnerName": "Blah", "OwnerType": "BusinessMan"},{"id": 234, "OwnerName": "Blah", "OwnerType": "BusinessMan"},{"id": 432, "OwnerName": "Blah", "OwnerType": "Test"},{"id": 112, "OwnerName": "Blah", "OwnerType": "BusinessMan"},{"id": 114, "OwnerName": "Blah", "OwnerType": "Test"}]

我需要获取array1的过滤数组，其中array2中的OwnerType为Test。 array1中的OwnerID链接到数组2中的id。我希望尽可能少地执行此操作。理想情况下，我主要想查看数组长度是否大于1，因为第一个数组应该只有一个类型。任何帮助表示赞赏。

编辑：

所需的输出应该是array1，如下所示：

[{"id": "-1","OwnerID": 777,"Admin": "true"},{"id": "-1","OwnerID": 555,"Admin": "true"}]

Answer 1

两个嵌套循环应该很容易解决：

var array_result = [];

for(var i = 0; i < array1.length; i++){
    for(var j = 0; j < array2.length; j++){
        if(array2[j].id == array1[i].OwnerID && array2[j].OwnerType == "Test")
            array_result.push(array1[i]);
    }
}

如果array2是一个关联数组，将id作为键，那么过滤的复杂性就会大大降低。

Answer 2

首先，您要返回array2中具有匹配id（array1）和OwnerID（array2）值的所有对象。

// array of `OwnerID` values
var idArr = array1.map(function(obj) { return obj.OwnerID; });

然后，您只获得来自array2的具有匹配id（array1 OwnerID且OwnerType Test的对象}。

// filter array2 by matches
var matches = array2.map(function(obj) { 
  return idArr.indexOf(obj.id) > -1 && obj.OwnerType === 'Test'; 
});

结果matches将是一个具有正确id和OwnerType Test的对象数组。

Answer 3

答案我最终使用

array1.filter(ar1 => array2.filter(ar2 => ar2.OwnerType == 'Test' && ar2.id == ar1.OwnerID).length > 0).length > 1

感谢大家的帮助

两个对象数组需要根据其他对象过滤一个对象

3 个答案: