对于iPhone,我可以通过执行以下操作检测到应用程序在模拟器中运行:
var isSumlator = ObjCRuntime.Runtime.Arch == ObjCRuntime.Arch.SIMULATOR;
在Xamarin.Android中检测模拟器的最佳等价物是什么?
答案 0 :(得分:4)
这取决于您的目标,如果这仅用于本地调试测试,或者您是否计划将其保留在代码中以便在最终用户环境中进行测试。
由于Android的世界非常庞大,这是一种不断发展的方法,基于我们在野外看到的:
public bool isEmulator(bool LicensedPlayers = false)
{
var detect = 0;
try
{
var teleManager = (TelephonyManager)GetSystemService(TelephonyService);
string networkOperator = "";
try
{
networkOperator = teleManager.NetworkOperator;
if (LicensedPlayers)
{
if ((teleManager.NetworkOperatorName == "T-Mobile") &&
(Build.Radio == "unknown") &&
(Build.Serial == "unknown") &&
(Build.Manufacturer == "samsung"))
{
D.WriteLine("BlueStacks (OS-X) Player");
detect += 1;
}
}
}
catch
{
networkOperator = "";
D.WriteLine("TelephonyService Exceptiion, custom emulator");
detect += 1;
}
if (networkOperator.Contains("Android"))
{
D.WriteLine("Google's Android Emulator");
detect += 1;
}
}
catch
{
D.WriteLine("TelephonyService not available, custom emulator");
detect += 1;
}
if (LicensedPlayers)
{
if (Build.Display.Contains("andy") || (Build.Hardware.Contains("andy")))
{
D.WriteLine("Andy Player");
detect += 1;
}
}
if (Build.Hardware.Contains("goldfish"))
{
D.WriteLine("Goldfish-based Emulator");
detect += 1;
}
if (Build.Display.ToLowerInvariant().Contains("xamarin"))
{
D.WriteLine("Xamarin Android Player");
detect += 1;
}
if (Build.Hardware.Contains("vsemu"))
{
D.WriteLine("Visual Studio Android Emulator");
detect += 1;
}
if (Build.Host.Contains("genymobile") || (Build.Manufacturer.ToLowerInvariant().Contains("genymotion")))
{
D.WriteLine("Genymotion Android Emulator");
detect += 1;
}
if (Build.Hardware.Contains("vbox") && Build.Hardware.Contains("86"))
{
D.WriteLine("VirtualBox-based Emulator");
detect += 1;
}
return detect > 0;
}
更新:修复了多个平台上的XAP仿真器检测
答案 1 :(得分:3)
string fing = Build.Fingerprint;
bool isEmulator=false;
if (fing != null) {
isEmulator = fing.Contains("vbox") || fing.Contains("generic") || fing.Contains("vsemu");
}
答案 2 :(得分:3)
使用Xamarin.Essentials;
var isSimulator = DeviceInfo.DeviceType == DeviceType.Virtual;