我已阅读此帖https://stackoverflow.com/a/18295177/6188148 但我的json看起来有点不同。这是我的json。
[{"ID":1,"Name":"Suzy","ParentID":0},
{"ID":2,"Name":"Somi","ParentID":1},
{"ID":3,"Name":"Romi","ParentID":2},
{"ID":4,"Name":"Jumi","ParentID":3},
{"ID":5,"Name":"Gargi","ParentID":0},
{"ID":6,"Name":"Sujoy","ParentID":5},
{"ID":7,"Name":"Kamal","ParentID":6},
{"ID":8,"Name":"Joy","ParentID":0},
{"ID":9,"Name":"Sumana","ParentID":8},
{"ID":10,"Name":"Alex","ParentID":0}]
在我的案例中,与ID和ParentID建立关系。关系可以嵌套到第n级。所以告诉我如何使用ng-repeat来显示父母和子女数据。
<div ng-app="myApp">
<ul class="nav nav-pills" data-ng-controller= "MasterDetails" >
<li
data-ng-repeat="parent in details | filter: { ParentID: 0 }" >
<a href="#/customers"> {{ parent.Name }} </a>
<ul>
<li data-ng-repeat="child in details | filter: { ParentID: parent.ID }">
{{ child.Name }}
</li>
</ul>
</li>
</ul>
</div>
angular.module("myApp", []).
controller("MasterDetails", ['$scope', function($scope) {
$scope.details = [{"ID":1,"Name":"Suzy","ParentID":0},
{"ID":2,"Name":"Somi","ParentID":1},
{"ID":3,"Name":"Romi","ParentID":2},
{"ID":4,"Name":"Jumi","ParentID":3},
{"ID":5,"Name":"Gargi","ParentID":0},
{"ID":6,"Name":"Sujoy","ParentID":5},
{"ID":7,"Name":"Kamal","ParentID":6},
{"ID":8,"Name":"Joy","ParentID":0},
{"ID":9,"Name":"Sumana","ParentID":8},
{"ID":10,"Name":"Alex","ParentID":0}];
}]);
这里是jsfiddle https://jsfiddle.net/tridip/s0svpaev/2/
上面的代码正在运行但没有得到正确的输出。 层次结构应该是这样的
Suzy
Somi
Romi
Jumi
Gargi
Sujoy
Kamal
Joy
Sumana
Alex
我在代码中犯了错误,我没有得到正确的输出。感谢
答案 0 :(得分:2)
根据您的链接,我创建了此plnkr并进行了一些修改,以满足您的需求。
我刚刚在控制器中添加了 getSubPeople 函数,以获取一个代表较长父母的子数组,并立即将它们传递给子渲染指令:
我们的部分:
<ul>
<li ng-repeat="p in peoples">
{{p}}
<div ng-switch on="p.ParentID > 0">
<div ng-switch-when="true">
<div ng-init="peoples = getSubPeople(p.ParentID);" ng-include="'partialPeoples.html'"></div>
</div>
</div>
</li>
</ul>
我们的控制器:
var app = angular.module('angularjs-starter', []);
app.controller('MainCtrl', function($scope, $http) {
$scope.peoples = [{"ID":1,"Name":"Suzy","ParentID":0},
{"ID":2,"Name":"Somi","ParentID":1},
{"ID":3,"Name":"Romi","ParentID":2},
{"ID":4,"Name":"Jumi","ParentID":3},
{"ID":5,"Name":"Gargi","ParentID":0},
{"ID":6,"Name":"Sujoy","ParentID":5},
{"ID":7,"Name":"Kamal","ParentID":6},
{"ID":8,"Name":"Joy","ParentID":0},
{"ID":9,"Name":"Sumana","ParentID":8},
{"ID":10,"Name":"Alex","ParentID":0}];
$scope.getSubPeople = function(parentId) {
var arr = [];
for(var i=parentId; i>0 ; i--){
arr.push($scope.peoples[i-1]);
}
return arr;
}
});
答案 1 :(得分:1)
假设包括 jQuery 和不关心选择性能,这个anwser可以满足您的要求。
angular.module('app', [])
.controller('appCtrl', function($scope) {
$scope.data = [{
"ID": 1,
"Name": "Suzy",
"ParentID": 0
}, {
"ID": 2,
"Name": "Somi",
"ParentID": 1
}, {
"ID": 3,
"Name": "Romi",
"ParentID": 2
}, {
"ID": 4,
"Name": "Jumi",
"ParentID": 3
}, {
"ID": 5,
"Name": "Gargi",
"ParentID": 0
}, {
"ID": 6,
"Name": "Sujoy",
"ParentID": 5
}, {
"ID": 7,
"Name": "Kamal",
"ParentID": 6
}, {
"ID": 8,
"Name": "Joy",
"ParentID": 0
}, {
"ID": 9,
"Name": "Sumana",
"ParentID": 8
}, {
"ID": 10,
"Name": "Alex",
"ParentID": 0
}];
})
.directive('tree',function($filter){
return {
restrict:'EA',
scope:{
data:'='
},
link:function(scope,element,attrs){
scope.data = $filter('orderBy')(scope.data,'ParentID');
var html = $('<ul id="tree-outer-0"></ul>');
element.append(html);
angular.forEach(scope.data,function(val,index){
var tree = $('<li id="tree-inner-'+val.ID+'">'+val.Name+'</li>');
var parent = $('ul#tree-outer-'+val.ParentID);
if(parent.length){
parent.append(tree);
}else{
var parents = $('li#tree-inner-'+val.ParentID);
var parent = $('<ul id="tree-outer-'+val.ParentID+'"></ul>');
parent.appendTo(parents).append(tree);
}
});
}
}
});
&#13;
<script src="//cdn.bootcss.com/angular.js/1.5.5/angular.min.js"></script>
<script src="//cdn.bootcss.com/jquery/2.1.4/jquery.js"></script>
<div ng-app="app" ng-controller="appCtrl">
<tree data="data"></tree>
</div>
&#13;