Question

我有两个数组，就像是

var array1=['a1','a2','a3','a4','a5,','a6','a7','a8','a9','a10,','a11','a12'----];
var array2=['b1','b2','b3','b4',----];
var result= [];

我想将结果数组显示为

result= ['a1','a2','b1','a3','a4,','a5','a6','a7','a8','a9,','a10','a11','b2','a12']

第二个数组'array2'值位于3,12,19,28,35 ...（系列如3,3 + 9,12 + 7,19 + 9,28 + 7等）如果'array1'的值小于'array2'，那么值应该连续放在'result []'中，例如：

array1=['a1','a2','a3'];
array2=['b1','b2','b3'];

然后

result=['a1','a2','b1','a3','b2','b3'];

如何使用jquery实现这一点？

Answer 1

快速管理此方法。但它可以进行优化。

var array1=['a1','a2','a3','a4','a5,','a6','a7','a8','a9','a10,','a11','a12'];
var array2=['b1','b2','b3','b4'];
document.body.innerHTML += "arr1:" + array1 + "<br/>";
    document.body.innerHTML += "arr2:" + array2 + "<br/>";
var result= [];

var index=0;
var lastInsertedBindex=0;
var step1 = 9;
var step2 = 7;
var lastUsedStep = step2;
var nextStepIndex = 3;
elements = true;
var indexFromA = 0;
var indexFromB = 0;
var elementsExists = true;
do{
  if( index != nextStepIndex ){
    if( undefined != array1[indexFromA] ){
      result.push( array1[indexFromA]);
      indexFromA++;
    } else if( undefined != array2[indexFromB]){
      result.push( array2[indexFromB]);
      indexFromB++;
    } else 
      elementsExists = false;
    
    index++;
    continue;
  }else{
    if( undefined != array2[indexFromB] ){
      result.push(array2[indexFromB]);
      indexFromB++;
      lastUsedStep = lastUsedStep == step1 ? step2 : step1;
      nextStepIndex = nextStepIndex + lastUsedStep; 
    } else if( undefined != array1[indexFromA]) {
      result.push(array1[indexFromA]);
      indexFromA++;
      
    } else 
       elementsExists = false;
        
    index++;
  }
  
  
}while(elementsExists);
document.body.innerHTML += "res:" + result;

Answer 2

这应该有用。

＆＃13;

// Create arrays
var array1 = [];
var array2 = [];
for(i=1;i<100;i++){
  array1[array1.length] = "a"+i;
}
for(i=2;i<50;i++){
  array2[array2.length] = "b"+i;
}

// The function
function coupleArrays(array1, array2){
  var newArray = [];
  var jump = 9; // first jump
  var pos = 3; // Starting point

  while(array1.length > 0){
    var i = newArray.length;

    if(i == pos-1 && array2.length != 0){
      // remove first from array2 and add to newArray
      newArray[i] = array2.shift(); 

      pos += jump; // add the jump to get new position

      // set jump to 9 or 7
      if(jump == 9) jump = 7;
      else jump = 9;

    }else{
      // remove first from array1 and add to newArray
      newArray[i] = array1.shift();
    }
  }
  return newArray;
}
var coupled = coupleArrays(array1, array2);

// Just to show output
for(i=0;i<coupled.length;i++){
  var nr = i;
  if( nr < 10 ) nr = "0"+nr;
  if( nr < 100 ) nr = "0"+nr;
  document.write( nr + ": " + coupled[i] + "<br />");
}

＆＃13;

Answer 3

你可以做的一种方法是循环<h:form id="saveForm" styleClass="form"> <h:inputText value="#{wordController.currentWord}" id="words" /> <h:commandButton action="#{wordController.addWord()}" type="submit" value="+"> <f:ajax render="wordlist" /> </h:commandButton> <h:panelGroup id="wordlist"> ....，将前x个项切片到结果（取决于它可能是3,7或9的迭代）并附加{{1的当前索引}}。然后，一旦array2中的元素用尽，继续添加array2中的元素。

array1

array2

Answer 4

您可以使用递归函数来解决此问题：

var array1 = [];
var array2 = [];

// Preparing data
for (var i = 0, len = 100; i < len; ++i) {
  array1[i] = 'a' + (i + 1);
  array2[i] = 'b' + (i + 1);
}

var index = 3;
function insert (arr1, arr2, i) {
  // Insert element to array
  array1.splice(index - 1, 0, array2[i]);
  index = ((index % 2) == 1) ? index + 9 : index + 7;
  if ( index < arr2.length - 1) { insert(arr1, arr2, i + 1) }
  return;
}

insert(array1, array2, 0);
array1.forEach( function (item) {
  let output = (item.indexOf('b') !== -1) ? '<b>' + item + ' </b>' 
              : item + ' ';
  $('#result').append(output);
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="result"></div>

如何使用jquery组合两个数组

4 个答案: