Question

下面是我的代码，它总是让我返回true，所以我的行动已经提交。任何人都可以帮我解决这个问题。在得到ajax的响应后，即使我写了return false，它也会成立。

<?php
    if(isset($_POST['submit'])){
        die("lokesh");
    }
    ?>
    <html>
        <head>
            <script src="js/jquery-1.8.2.min.js"></script>
            <script>
                function checkjs(){
                    if(document.getElementById('a').value==""){
                        alert("insert a");
                        return false;
                    }
                    if(document.getElementById('b').value==""){
                        alert("insert b");
                        return false;
                    }
                    if(document.getElementById('c').value==""){
                        alert("insert c");
                        return false;
                    }
                    var companyname = document.getElementById('b').value;
                    var username = document.getElementById('c').value;
                    jQuery.ajax({
                type: "POST",           
                dataType: "json",   
                url:'checkexisting.php',
                data:{
                    companyname: companyname,username: username,
                },
                success:function(response) {
                                alert("response"+response);
                                return false;
                }
                });                
                }
            </script>
        </head>
        <body>
            <form action="#" method="post" name="form">
                <input type="text" id="a">
                <input type="text" id="b">
                <input type="text" id="c">
                <input type="submit" name="submit" onclick="return checkjs();">
            </form>
        </body>
    </html>

以下代码适用于checkexisting.php

<?php
$companyname = $_REQUEST['companyname'];
$username = $_REQUEST['username'];
$response = $companyname.$username;
echo json_encode($response);
?>

ajax总是变为true并且提交了action

0 个答案: