Question

在AngularJS中，如何在按钮中设置ng-disabled属性，以便在用户输入小数输入时不会启用它？

目前，当我输入“0.1”但该按钮已启用时，该框以红色突出显示。

<input type="number" ng-model="person.age" id="age" name="age" placeholder="Age" 
    class="form-control" min="0" ng-change="compute()" ng-required="!person.age">

<button id="ok-btn" class="btn btn-primary" ng-click="okEdit(person)" 
    ng-disabled="(!person.age && person.age !== 0)">OK</button>

Answer 1

检查person.age值是否等于解析值，如：

angular.module('app', []).controller('ctrl', function($scope) {
  $scope.person = {};
  $scope.isDisabled = function(person) {
    return parseInt(person.age) !== person.age
  }
})

<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<div ng-app="app" ng-controller="ctrl">
  <input type="number" ng-model="person.age" name="age" placeholder="Age" class="form-control" min="0" ng-required="!person.age">
  <button class="btn btn-primary" ng-click="okEdit(person)" ng-disabled="isDisabled(person)">OK</button>
</div>

当输入为十进制

1 个答案: