我希望根据特定player_id以尽可能最高的contract_id对数据进行分组。 这听起来很简单但是没有按预期工作。
SELECT distinct(f1.player_id), f1.contract_id,f1.feature_id
from (select p.player_id,p.player_name, p.player_no, CASE c.action
when 'submit' then 'تقديم'
when 'approve' then 'موافقة'
when 'reject' then 'رفض'
when 'object' then 'اعتراض'
when 'resubmit' then 'اعادة تقديم'
END as action, c.new_time, Case co.status
when 'free' then 'حر'
when 'active' then 'نشط'
when 'expired' then 'منتهي'
when 'loan' then 'معار'
when 'loan expire' then 'ااعارة منتهية'
END as status, co.contract_id,c.feature_id
FROM contract co
INNER JOIN player_profile p ON p.player_id = co.player_id
INNER JOIN new_request c ON c.contract_id = co.contract_id
INNER JOIN club cl ON co.club_id = cl.club_id
where co.reqeust_type='new'
) as f1
order by f1.player_id asc;
数据集: 完整数据集
SELECT distinct(f1.player_id), f1.contract_id,f1.feature_id
from (select p.player_id,p.player_name, p.player_no, CASE c.action
when 'submit' then 'تقديم'
when 'approve' then 'موافقة'
when 'reject' then 'رفض'
when 'object' then 'اعتراض'
when 'resubmit' then 'اعادة تقديم'
END as action, c.new_time, Case co.status
when 'free' then 'حر'
when 'active' then 'نشط'
when 'expired' then 'منتهي'
when 'loan' then 'معار'
when 'loan expire' then 'ااعارة منتهية'
END as status, co.contract_id,c.feature_id
FROM contract co
INNER JOIN player_profile p ON p.player_id = co.player_id
INNER JOIN new_request c ON c.contract_id = co.contract_id
INNER JOIN club cl ON co.club_id = cl.club_id
where co.reqeust_type='new'
) as f1
group by f1.player_id
order by f1.player_id asc;
查询数据集
我想获得Player_ID 7和合同ID 301。
答案 0 :(得分:1)
考虑你的“基础”子查询:
SELECT p.player_id,p.player_name, p.player_no,
CASE c.action
when 'submit' then 'تقديم'
when 'approve' then 'موافقة'
when 'reject' then 'رفض'
when 'object' then 'اعتراض'
when 'resubmit' then 'اعادة تقديم'
END as action,
c.new_time,
CASE co.status
when 'free' then 'حر'
when 'active' then 'نشط'
when 'expired' then 'منتهي'
when 'loan' then 'معار'
when 'loan expire' then 'ااعارة منتهية'
END as status,
co.contract_id,
c.feature_id
FROM contract co
INNER JOIN player_profile p ON p.player_id = co.player_id
INNER JOIN new_request c ON c.contract_id = co.contract_id
INNER JOIN club cl ON co.club_id = cl.club_id
WHERE co.reqeust_type='new'
如果你想获得每位玩家最高的contract_id
,你应该选择MAX(contract_id)
和GROUP BY
玩家
SELECT MAX(co.contract_id),
p.player_id,p.player_name, p.player_no,
CASE c.action
when 'submit' then 'تقديم'
when 'approve' then 'موافقة'
when 'reject' then 'رفض'
when 'object' then 'اعتراض'
when 'resubmit' then 'اعادة تقديم'
END as action,
c.new_time,
CASE co.status
when 'free' then 'حر'
when 'active' then 'نشط'
when 'expired' then 'منتهي'
when 'loan' then 'معار'
when 'loan expire' then 'ااعارة منتهية'
END as status,
co.contract_id,
c.feature_id
FROM contract co
INNER JOIN player_profile p ON p.player_id = co.player_id
INNER JOIN new_request c ON c.contract_id = co.contract_id
INNER JOIN club cl ON co.club_id = cl.club_id
WHERE co.reqeust_type='new'
GROUP BY co.player_id
然后,您只能从此查询中检索所需的播放器,如下所示:
SELECT *
FROM
(
SELECT MAX(co.contract_id) AS contractid,
p.player_id,p.player_name, p.player_no,
CASE c.action
when 'submit' then 'تقديم'
when 'approve' then 'موافقة'
when 'reject' then 'رفض'
when 'object' then 'اعتراض'
when 'resubmit' then 'اعادة تقديم'
END as action,
c.new_time,
CASE co.status
when 'free' then 'حر'
when 'active' then 'نشط'
when 'expired' then 'منتهي'
when 'loan' then 'معار'
when 'loan expire' then 'ااعارة منتهية'
END as status,
co.contract_id,
c.feature_id
FROM contract co
INNER JOIN player_profile p ON p.player_id = co.player_id
INNER JOIN new_request c ON c.contract_id = co.contract_id
INNER JOIN club cl ON co.club_id = cl.club_id
WHERE co.reqeust_type='new'
GROUP BY co.player_id
) T
WHERE player_id = 7