当用户在ASP.NET中使用C#将图像文件上传到SQL Server 2005时,如何动态插入图像?这是为了让用户在我的网络应用中上传他们的个人资料照片。它与使用C#的Windows应用程序的完成方式有很大不同吗?
答案 0 :(得分:2)
网上有一公吨的例子:
http://aspalliance.com/138
http://www.4guysfromrolla.com/articles/120606-1.aspx
http://www.aspfree.com/c/a/ASP.NET/Uploading-Images-to-a-Database--C---Part-I/
您应该能够遵循其中任何一项来完成您想要的任务。
答案 1 :(得分:1)
与WinForms中的方式相同。获取byte[]
并与image
列相同。但我强烈建议使用文件系统来存储图片。 DB用于关系数据,文件系统用于原始字节。
答案 2 :(得分:0)
以下是在C#中将图像插入数据库的代码示例。您将需要粗略支持表,图片应该是一个字节字段并保留图片类型,以便您可以稍后检索图像以显示它。除此之外,您还需要在页面上放置一个文件输入框和一个提交按钮。
public void AddImage(object sender, EventArgs e)
{
int intImageSize;
String strImageType;
Stream ImageStream;
FileStream fs = File.OpenRead(Request.PhysicalApplicationPath + "/Images/default_image.png");
Byte[] ImageContent;
if (PersonImage.PostedFile.ContentLength > 0)
{
intImageSize = PersonImage.PostedFile.ContentLength;
strImageType = PersonImage.PostedFile.ContentType;
ImageStream = PersonImage.PostedFile.InputStream;
ImageContent = new Byte[intImageSize];
int intStatus;
intStatus = ImageStream.Read(ImageContent, 0, intImageSize);
}
else
{
strImageType = "image/x-png";
ImageContent = new Byte[fs.Length];
fs.Read(ImageContent, 0, ImageContent.Length);
}
SqlConnection objConn = new SqlConnection(ConfigurationManager.AppSettings["conn"]);
SqlCommand objCmd;
string strCmd;
strCmd = "INSERT INTO ImageTest (Picture, PictureType) VALUES (@Picture, @PictureType)";
objCmd = new SqlCommand(strCmd, objConn);
SqlParameter prmPersonImage = new SqlParameter("@Picture", SqlDbType.Image);
prmPersonImage.Value = ImageContent;
objCmd.Parameters.Add(prmPersonImage);
objCmd.Parameters.AddWithValue("@PictureType", strImageType);
lblMessage.Visible = true;
try
{
objConn.Open();
objCmd.ExecuteNonQuery();
objConn.Close();
lblMessage.Text = "ImageAdded!";
}
catch
{
lblMessage.Text = "Error occured the image has not been added to the database!";
}
}
public void AddImage(object sender, EventArgs e)
{
int intImageSize;
String strImageType;
Stream ImageStream;
FileStream fs = File.OpenRead(Request.PhysicalApplicationPath + "/Images/default_image.png");
Byte[] ImageContent;
if (PersonImage.PostedFile.ContentLength > 0)
{
intImageSize = PersonImage.PostedFile.ContentLength;
strImageType = PersonImage.PostedFile.ContentType;
ImageStream = PersonImage.PostedFile.InputStream;
ImageContent = new Byte[intImageSize];
int intStatus;
intStatus = ImageStream.Read(ImageContent, 0, intImageSize);
}
else
{
strImageType = "image/x-png";
ImageContent = new Byte[fs.Length];
fs.Read(ImageContent, 0, ImageContent.Length);
}
SqlConnection objConn = new SqlConnection(ConfigurationManager.AppSettings["conn"]);
SqlCommand objCmd;
string strCmd;
strCmd = "INSERT INTO ImageTest (Picture, PictureType) VALUES (@Picture, @PictureType)";
objCmd = new SqlCommand(strCmd, objConn);
SqlParameter prmPersonImage = new SqlParameter("@Picture", SqlDbType.Image);
prmPersonImage.Value = ImageContent;
objCmd.Parameters.Add(prmPersonImage);
objCmd.Parameters.AddWithValue("@PictureType", strImageType);
lblMessage.Visible = true;
try
{
objConn.Open();
objCmd.ExecuteNonQuery();
objConn.Close();
lblMessage.Text = "ImageAdded!";
}
catch
{
lblMessage.Text = "Error occured the image has not been added to the database!";
}
}