我有数组1 :
Array
(
[0] => Array
(
[recomendation_id] => 3588
[employee_id] => 90141063
[attendance_type_id] => 2
[start_dtm] => 2016-05-17 10:32:00
[end_dtm] =>
[request_message] => test notif
[recomendation_status_id] => 1
[last_update_dtm] => 2016-05-17 10:32:43
[employee_name] => Nike Yulistia Angreni
[attd_type_name] => Permittance
[status_name] => Request
)
)
数组2 :
Array
(
[0] => Array
(
[valuator1] => Wulan Lastia Permana
)
)
我想在一个数组中创建数组值。我想要这样的结果:
Array
(
[0] => Array
(
[recomendation_id] => 3588
[employee_id] => 90141063
[attendance_type_id] => 2
[start_dtm] => 2016-05-17 10:32:00
[end_dtm] =>
[request_message] => test notif
[recomendation_status_id] => 1
[last_update_dtm] => 2016-05-17 10:32:43
[employee_name] => Nike Yulistia Angreni
[attd_type_name] => Permittance
[status_name] => Request
[valuator1] => Wulan Lastia Permana
)
)
是否可以像这样加入?
答案 0 :(得分:11)
您必须使用array_replace_recursive:
Array
(
[0] => Array
(
[recomendation_id] => 3588
[employee_id] => 90141063
[attendance_type_id] => 2
[start_dtm] => 2016-05-17 10:32:00
[end_dtm] =>
[request_message] => test notif
[recomendation_status_id] => 1
[last_update_dtm] => 2016-05-17 10:32:43
[employee_name] => Nike Yulistia Angreni
[attd_type_name] => Permittance
[status_name] => Request
[valuator1] => Wulan Lastia Permana
)
)
结果:
Array
(
[0] => Array
(
[recomendation_id] => 3588
[employee_id] => 90141063
[attendance_type_id] => 2
[start_dtm] => 2016-05-17 10:32:00
[end_dtm] =>
[request_message] => test notif
[recomendation_status_id] => 1
[last_update_dtm] => 2016-05-17 10:32:43
[employee_name] => Nike Yulistia Angreni
[attd_type_name] => Permittance
[status_name] => Request
)
[1] => Array
(
[valuator1] => Wulan Lastia Permana
)
)
您的Eval
如果您使用array_merge_recursive,则output将为:
string QuestionOption_Upsert(string UserCode, string ExamCode, QuesAnswer[] Answer);
答案 1 :(得分:2)
您可以使用array_merge_recursive功能
$result = array_merge_recursive($array1, $array2);
答案 2 :(得分:0)
是的,有可能。让您的第一个数组为$arr1
,第二个数组为$arr2
。
只需为第一个数组指定一个新字段,第一个数组将使用第二个数组key, value pair
进行更新。
$arr1[0]['valuator1'] = $arr2[0]['valuator1'];
print_r($arr1);
<强>结果:强>
Array
(
[0] => Array
(
[recomendation_id] => 3588
[employee_id] => 90141063
[attendance_type_id] => 2
[start_dtm] => 2016-05-17 10:32:00
[end_dtm] =>
[request_message] => test notif
[recomendation_status_id] => 1
[last_update_dtm] => 2016-05-17 10:32:43
[employee_name] => Nike Yulistia Angreni
[attd_type_name] => Permittance
[status_name] => Request
[valuator1] => Wulan Lastia Permana
)
)
答案 3 :(得分:0)
在我看来,这不是最佳选择,但仍会解决您的问题。
foreach ($arr2 as $k => $v) {
$arr1[$key] = array_merge($arr1[$key], $v);
}
这将遍历第二个数组并将每个值与第一个数组合并。
注意:两个数组中的数组键应该相同,以便工作。