NSURL SKSpriteNode按钮的多个else If语句 - 6个中的2个不打开？

Question

我根本无法理解为什么Facebook和Twitter按钮没有打开？

    override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
    for touch in touches {
        let location = touch.locationInNode(self)


// Reviews & Rating
        let reviewsAppString = "itms-apps://ax.itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=APP_ID"
        let reviewsApp = NSURL(string: reviewsAppString)
        let reviewsWebString = "https://itunes.apple.com/us/developer/DEVELOPER_NAME/DEVELOPER_ID"
        let reviewsWeb = NSURL(string: reviewsWebString)

// Facebook
        let fbWebString = "https://www.facebook.com/PAGE_NAME"
        let fbWeb = NSURL(string: fbWebString)
        let fbAppString = "fb://profile/PAGE_ID"
        let fbApp = NSURL(string: fbAppString)
// Twitter
        let twWebString = "https://twitter.com/USER_NAME"
        let twWeb = NSURL(string: twWebString)
        let twAppString = "twitter://user?screen_name=USER_ID"
        let twApp = NSURL(string: twAppString)



        if nodeAtPoint(location) == gameCenterButton {
            NSNotificationCenter.defaultCenter().postNotificationName("showLeaderboard", object: nil)
        }
        else if nodeAtPoint(location) == playButton {
            presentScene(GameScene())
        }
        else if nodeAtPoint(location) == soundButton {
            toggleSound()
        }

// REVIEWS AND RATINGS
        else if nodeAtPoint(location) == rateButton {
            if (UIApplication.sharedApplication().canOpenURL(reviewsApp!)) {
                UIApplication.sharedApplication().openURL(reviewsApp!)
        }
            else {
            if  UIApplication.sharedApplication().canOpenURL(reviewsWeb!)   {
                UIApplication.sharedApplication().openURL(reviewsWeb!)
            }
// FACEBOOK
        else if nodeAtPoint(location) == facebookButton {
            if (UIApplication.sharedApplication().canOpenURL(fbApp!)) {
                UIApplication.sharedApplication().openURL(fbApp!)
            }
            else {
            if  UIApplication.sharedApplication().canOpenURL(fbWeb!)   {
                UIApplication.sharedApplication().openURL(fbWeb!)
                }
 // TWITTER
        else if nodeAtPoint(location) == twitterButton {
            if (UIApplication.sharedApplication().canOpenURL(twApp!)) {
                UIApplication.sharedApplication().openURL(twApp!)
            }
            else {
                if  UIApplication.sharedApplication().canOpenURL(twWeb!)   {
                    UIApplication.sharedApplication().openURL(twWeb!)
                }

我只能认为我使用了太多其他if语句并且有更好/更清晰的方法来做，但我很难过！

Xcode 7.3.1 - Swift 2.2