MySql存储过程,如何使用CONCAT

时间:2016-05-16 18:09:06

标签: mysql sql variables stored-procedures

基本上我有以下存储过程:

BEGIN
SET @query := CONCAT("SELECT *,
sqrt( 
        (POW(a.Latitude - co.CenterLatitude, 2)* 68.1 * 68.1) + 
        (POW(a.Longitude - co.CenterLongitude, 2) * 53.1 * 53.1) 
 ) AS distance
FROM table1 as r
JOIN table2 as co ON co.field1 = r.field2
JOIN table3 AS a ON r.field1 = a.field2
WHERE ",rid);

PREPARE stmt FROM @query;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

END

它有以下传递:

IN rid varchar(500), lat double, lon double

但我需要传递纬度和经度变量。我已经尝试设置它们然后将它们添加到查询中但它没有识别它们。这就是我想做的不成功的事情:

    BEGIN
    SET @lat := lat;
    SET @lon := lon;
    SET @query := CONCAT("SELECT *,
    sqrt( 
            (POW(a.Latitude - @lat, 2)* 68.1 * 68.1) + 
            (POW(a.Longitude - @lon, 2) * 53.1 * 53.1) 
     ) AS distance
    FROM table1 as r
    JOIN table2 as co ON co.field1 = r.field2
    JOIN table3 AS a ON r.field1 = a.field2
    WHERE ",rid);

    PREPARE stmt FROM @query;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;

    END

我不知道如何做到这一点。有没有人有什么建议?提前谢谢!!

2 个答案:

答案 0 :(得分:3)

您可以将?占位符放在预准备语句中,然后在执行时提供值。

SET @query := CONCAT("SELECT *,
sqrt( 
        (POW(a.Latitude - ?, 2)* 68.1 * 68.1) + 
        (POW(a.Longitude - ?, 2) * 53.1 * 53.1) 
 ) AS distance
FROM table1 as r
JOIN table2 as co ON co.field1 = r.field2
JOIN table3 AS a ON r.field1 = a.field2
WHERE ",rid);
PREPARE stmt FROM @query;
EXECUTE stmt USING @lat, @lon;

答案 1 :(得分:1)

Barmar的答案将是我首选的解决方案,但举一个例子来说明我最初的评论建议......

BEGIN
SET @query := CONCAT("SELECT *,
sqrt( 
        (POW(a.Latitude - ", lat, ", 2)* 68.1 * 68.1) + 
        (POW(a.Longitude - ", lon, ", 2) * 53.1 * 53.1) 
 ) AS distance
FROM table1 as r
JOIN table2 as co ON co.field1 = r.field2
JOIN table3 AS a ON r.field1 = a.field2
WHERE ",rid);

PREPARE stmt FROM @query;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

END