Question

需要您的帮助才能找到解决方案。我有以下json

[{ “源”： “AA”， “目标”： “BB”， “指标”： “10”， “local_interface”： “100”， “remote_interface”： “200”}， { “源”： “AA”， “目标”： “BB”， “指标”： “10”， “local_interface”： “111”， “remote_interface”： “222”}， { “源”： “BB”， “目标”： “AA”， “指标”： “10”， “local_interface”： “200”， “remote_interface”： “100”}]

目标是：

获取第一个元素（即：pattern）作为source / target / local_interface
搜索匹配source = pattern.target，target = pattern.source，remote_interface = pattern.local_interface
从json中删除元素。

希望这是有道理的。

Answer 1

你是在追求像这样简单的事情吗？

j = [{"source":"AA","target":"BB","metric":"10",
 "local_interface":"100","remote_interface":"200"},
 {"source":"AA","target":"BB","metric":"10",
 "local_interface":"111","remote_interface":"222"},
 {"source":"BB","target":"AA","metric":"10",
 "local_interface":"200","remote_interface":"100"}]

s = j[0]["source"]
print(s)
t = j[0]["target"]
print(t)
li = j[0]["local_interface"]
print(li)

print('Find source ==', t)
for i in range(1,3):
  if j[i]['source'] == t:
    print("Is match:", j[i])

print()

del(j[1])
print("after deletion:", j)

python json匹配多个并替换

1 个答案: