Question

我的数组如下：

:contains(X AND Y)
:contains(X(any number of characters)Y)

我想计算每个ID，数组中存在特定ID的次数，并得到如下结果：Array ( [0] => Array ( [id] => 48 [str] => String1 ) [1] => Array ( [id] => 48 [str] => String1 ) [2] => Array ( [id] => 49 [str] => String2 ) [3] => Array ( [id] => 49 [str] => String2 ) [4] => Array ( [id] => 47 [str] => String3 ) [5] => Array ( [id] => 47 [str] => String3 ) [6] => Array ( [id] => 49 [str] => String2 ) [7] => Array ( [id] => 48 [str] => String1 ) );，String2 count 3等等......

问题是id可以是任何东西，行是通过其他键从数据库中获取的。

我已经尝试了，但我得到的只是空键和数组中项目的总数：

String3 count 2

Answer 1

试试这个：

<?php 
$results = array(
    array("id" => '48','str' => "string1"),
    array("id" => '48','str' => "string1"),
    array("id" => '49','str' => "string1"),
    array("id" => '47','str' => "string1"),
    array("id" => '47','str' => "string1") 
    );
$count = array();
foreach($results as $r)
{
    @$count[$r['id']]++;  // it will add no of occurances of any id
}
print '<pre>';print_r($count);
exit;
?>

输出：

Array
(
    [48] => 2   // 48 id exist 2 times
    [49] => 1   // 49 id exist 1 times
    [47] => 2   // 47 id exist 2 times
)

Answer 2

$count = array();
foreach($results as $r)
{
    if (isset($count[$r['id']]) {
        $count[$r['id']]['count']++;
    } else {
        $count[$r['id']] = array('count' => 1, 'string' => $r['str']);
    }
}

所以你在一个数组中有计数和str

你也可以直接从数据库

获取

select str, count(id) from table_name group by id

Answer 3

简单地这样做：让您的数组名称为$array。

$arr = array();
foreach($array as $val){
    if(isset($arr[$val['id']]))
        $arr[$val['id']] = $arr[$val['id']] + 1;
    else
        $arr[$val['id']] = 1;
}

<强>结果

Array
(
    [48] => 3
    [49] => 3
    [47] => 2
)

Answer 4

使用array_column和array_count_values函数的简单解决方案：

$arr = [
    ['id' => 48, 'str' => 'String1'],
    ['id' => 48, 'str' => 'String1'],
    ['id' => 49, 'str' => 'String2'],
    ['id' => 50, 'str' => 'String3'],
];

$ids = array_column($arr, 'id');
$counts = array_count_values($ids);

print_r($counts);

输出：

Array
(
    [48] => 2
    [49] => 1
    [50] => 1
)

http://php.net/manual/en/function.array-count-values.php

Answer 5

由DB

制作

GridView1.AddNewRow()

从未知键计数数组值

5 个答案: